i'm trying to split a string using 2 separator and regex. My string is for example
"test 10 20 middle 30 - 40 mm".
and i would like to split in ["test 10", "20 middle 30", "40 mm"]. So, splittin dropping ' - ' and the space between 2 digits. I tried to do
result = re.split(r'[\d+] [\d+]', s)
> ['test 1', '0 middle 30 - 40 mm']
result2 = re.split(r' - |{\d+} {\d+}', s)
> ['test 10 20 middle 30', '40 mm']
Is there any reg expression to split in ['test 10', '20 middle 30', '40 mm'] ?
You may use
(?<=\d)\s+(?:-\s+)?(?=\d)
See the regex demo.
Details
(?<=\d) - a digit must appear immediately on the left\s+ - 1+ whitespaces(?:-\s+)? - an optional sequence of a - followed with 1+ whitespaces(?=\d) - a digit must appear immediately on the right.See the Python demo:
import re
text = "test 10 20 middle 30 - 40 mm"
print( re.split(r'(?<=\d)\s+(?:-\s+)?(?=\d)', text) )
# => ['test 10', '20 middle 30', '40 mm']
Data
k="test 10 20 middle 30 - 40 mm"
Please Try
result2 = re.split(r"(^[a-z]+\s\d+|\^d+\s[a-z]+|\d+)$",k)
result2
**^[a-z]**-match lower case alphabets at the start of the string and greedily to the left + followed by:
**`\s`** white space characters
**`\d`** digits greedily matched to the left
| or match start of string with digits \d+ also matched greedily to the left and followed by:
`**\s**` white space characters
**`a-z`** lower case alphabets greedily matched to the left
| or match digits greedily to the left \d+ end the string $
Output
