var asdf:Array = [ [1,1] ];
trace( asdf.indexOf( [1,1] ) ); // -1
Why can't indexOf() find the [1,1] array?
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3 Answers
Here is a little function I wrote a while ago that works great. I included a lot of comments and an example search/function to output the results.
// set up a multidimensional array that contains some data
var myArray:Array = new Array();
myArray.push(["granola","people... are great"," 4 ","10"]);
myArray.push(["bill","orangutan","buster","keaton"]);
myArray.push(["steve","gates","24","yes, sometimes"]);
myArray.push(["help","dave","jobs","hal"]);
// here we set up some properties on the array object to hold our search string and our results
myArray.myTarget = "steve";
myArray.myResults = [];
// now we call the search
myArray.forEach(multiSearch);
// this is the function that does all the heavy lifting....
function multiSearch(element:*, index:int, array:Array)
{
// see if we have a match in this array and pass back its index
for(var i:* in element)
{
if( element[i].indexOf( array.myTarget ) > -1 )
{
var tempArray:Array = array.myResults;
tempArray.push([index,i]);
array.myResults = tempArray;
}
}
}
// -------------------------------------------------------------------------------
// all the code below is OPTIONAL... it is just to show our results
// in the output window in Flash so you know it worked....
var printArray:Array = myArray.myResults;
for(var i:* in printArray)
{
trace("TARGET FOUND @: "+printArray[i][0]+", "+printArray[i][1]+" = "+myArray[ printArray[i][0] ][ printArray[i][1] ]);
}
// -------------------------------------------------------------------------------
3 Comments
exoboy
This is the bare-bones version (the only stuff you need to make it work, except for you array index content): var myArray:Array = new Array(); myArray.myTarget = "steve"; myArray.myResults = []; myArray.forEach(multiSearch); function multiSearch(element:*, index:int, array:Array) { for(var i:* in element) { if( element[i].indexOf( array.myTarget ) > -1 ) { var tempArray:Array = array.myResults; tempArray.push([index,i]); array.myResults = tempArray; } } }
embassyhill
Thanks. I just added a tiny new function ( asdf.find = function(){} ) inspired by your solution.
exoboy
Great! It is tough to always be able to interpret what bit people need... so I am always happy when a solution helps!
It fails because when you do a [x,y] you are creating a new array, adsf contains one array and indexOf search for another one.
try:
trace([1,1] == [1,1]);
You will see that it prints false, since array are compare by reference.
One quick indexOf function, arrange it to suit your needs:
function isElmEquals(e1:*, e2:*):Boolean {
return (e1==e2);
}
function isArrayEquals(a1:Array, a2:Array):Boolean {
if (a1==a2)
return true;
if ((a1==null) || (a2==null)) {
return false;
}
if (a1.length!=a2.length)
return false;
for (var i:int=0;i<a1.length;i++){
if (!isElmEquals(a1[i], a2[i]))
return false;
}
return true;
}
function indexOf(value:Array, into:Array):int{
var i:int = -1;
into.some(
function(item:*, index:int, array:Array):Boolean {
if (isArrayEquals(item as Array, value)) {
i = index;
return true;
}
return false;
}
);
return i;
}
var i:int=indexOf([1,1], [[-1,1], [0,1], [1,1], [1,-1]]);
trace(i);
var j:int=indexOf([1,2], [[-1,1], [0,1], [1,1], [1,-1]]);
trace(j);
