how I have a simple question. I need to convert a date in string format to a number:
time = '2014-03-05 07:22:26.976637+00:00'
type(time)
str
I would like to convert this date to a unique number
Thank you.
-
2This question already has an answer: stackoverflow.com/questions/466345/…romeric– romeric2015-09-22 21:54:29 +00:00Commented Sep 22, 2015 at 21:54
-
possible duplicate of python: convert date timestamp to epoch unix time and figure out number of days remaining?Chad S.– Chad S.2015-09-22 22:00:07 +00:00Commented Sep 22, 2015 at 22:00
-
Thank you very much to your answers, however I don't know which format use to convert my string to a date with strptime. I am doing ` dt = datetime.strptime(time, '%m/%d/%Y %I:%M:%S.%f')` but it does not workemax– emax2015-09-22 22:02:30 +00:00Commented Sep 22, 2015 at 22:02
Add a comment
|
2 Answers
In Python 3.7+:
>>> from datetime import datetime
>>> datetime.fromisoformat('2014-03-05 07:22:26.976637+00:00').timestamp()
1394004146.976637
There are two steps:
Convert input rfc-3339 time string into datetime object
#!/usr/bin/env python
from datetime import datetime
time_str = '2014-03-05 07:22:26.976637+00:00'
utc_time = datetime.strptime(time_str[:26], '%Y-%m-%d %H:%M:%S.%f')
assert time_str[-6:] == '+00:00'
Find number of the microseconds since Epoch for given datetime
from datetime import datetime, timedelta
epoch = datetime(1970, 1, 1)
def timestamp_microsecond(utc_time):
td = utc_time - epoch
assert td.resolution == timedelta(microseconds=1)
return (td.days * 86400 + td.seconds) * 10**6 + td.microseconds
print(timestamp_microsecond(utc_time))
# -> 1394004146976637
The advantage is that you could convert this unique number back to the corresponding UTC time:
utc_time = epoch + timedelta(microseconds=1394004146976637)
# -> datetime.datetime(2014, 3, 5, 7, 22, 26, 976637)
Follow the links if you need to support arbitrary utc offsets (not just UTC time).
If you need to accept a leap second as the input time; see Python - Datetime not accounting for leap second properly?
Comments
I would like to convert this date to a unique number
The standard unix thing to do would be to convert to seconds since epoch. However, if you just want a unique number:
>>> time = '2014-03-05 07:22:26.976637+00:00'
>>> int(''.join(c for c in time if c.isdigit()))
201403050722269766370000L
If, instead of a unique number, you want a python datetime object, then use:
>>> from dateutil import parser
>>> dt = parser.parse(time)
>>> dt
datetime.datetime(2014, 3, 5, 7, 22, 26, 976637, tzinfo=tzutc())
1 Comment
Hephaestus
To complete the answer, use: dt.timestamp() which returns a unix time stamp in seconds as a float.
