Error parsing json in android

Question

This is a json response that i'm unable to parse. Please help me to parse this response.

{ "status": "true", "data": { "userinfo": [ { "id": "77", "firstname": "Test", "lastname": "" } ] } }

And this is my android code.

protected Void doInBackground(Void... params) {

 ServiceHandler2 sh = new ServiceHandler2();

 String url="http://192.168.0.65/hostandguest/android/viewprofile?uid=77";

 String jsonStr = sh.makeServiceCall(url, ServiceHandler2.GET);

 Log.d("Response: ", "> " + jsonStr);

  if (jsonStr != null) {

    try {

         JSONObject jsonObj = new JSONObject(jsonStr);
         String status = jsonObj.getString("status");

          if (status.equalsIgnoreCase("true")) {

            JSONArray   Userarr=jsonObj.getJSONArray("userinfo");
            String  data=jsonObj.getString("data");
             for(int i=0;i<Userarr.length();i++)
              {
                JSONObject c = Userarr.getJSONObject(i);
                String Fname=c.getString("firstname");
                Fname_arr.add(Fname);
                Log.v("Fname",Fname);                   
              }
            }
            else {
                  Log.v("Status", "false");
                 }

            } catch (JSONException e) {
                e.printStackTrace();
            }
        }

        return null;
    }

Did you getting any response?? if yes then you can check my answer. it will work for you. — Pratik Butani
– Pratik Butani, Commented Sep 24, 2015 at 13:35

Praveen Sharma · Accepted Answer · 2015-09-24 13:24:24Z

1

get data josnObject first as:-

JSONArray   Userarr=jsonObj.getJsonObject("data").getJSONArray("userinfo");

answered Sep 24, 2015 at 13:24

Praveen Sharma

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Comments

John · Accepted Answer · 2015-09-24 13:23:55Z

1

JSONArray Userarr=jsonObj.getJSONArray("userinfo"); would require jsonObj to contain the array "userinfo". This is not the situation you have presented. That array is inside a json sub object named "data".

        JSONObject jsonSubObj = jsonObj.getJSONObject("data");
        JSONArray  Userarr=jsonSubObj.getJSONArray("userinfo");

should be a fix. I've not checked for other errors.

answered Sep 24, 2015 at 13:23

John

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Pratik Butani · Accepted Answer · 2015-09-24 13:31:55Z

You are getting first userinfo object and then after data it's wrong.

I had changed like the following way you have to do this thing.

userinfo is sub array of data object.

protected Void doInBackground(Void... params) {

        ServiceHandler2 sh = new ServiceHandler2();

        String url = "http://192.168.0.65/hostandguest/android/viewprofile?uid=77";

        String jsonStr = sh.makeServiceCall(url, ServiceHandler2.GET);

        Log.d("Response: ", "> " + jsonStr);
        if (jsonStr != null) {

            try {

                JSONObject jsonObj = new JSONObject(jsonStr);
                String status = jsonObj.getString("status");

                if (status.equalsIgnoreCase("true")) {

                    JSONObject dataObj = jsonObj.getJSONObject("data");
                    JSONArray infoObj = dataObj.getJSONArray("userinfo");

                    for (int i = 0; i < infoObj.length(); i++) {
                        JSONObject c = Userarr.getJSONObject(i);
                        String Fname = c.getString("firstname");
                        Fname_arr.add(Fname);
                        Log.v("Fname", Fname);
                    }
                } else {
                    Log.v("Status", "false");
                }
            } catch (JSONException e) {
                e.printStackTrace();
            }
        }
        return null;
    }

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