PHP: JSON decoding problem

Question

<?php
$handle = fopen("https://graph.facebook.com/[email protected]&type=user&access_token=2227472222|2.mLWDqcUsekDYK_FQQXYnHw__.3600.1279803900-100001310000000|YxS1eGhjx2rpNYzzzzzzzLrfb5hMc.", "rb");
$json = stream_get_contents($handle);
fclose($handle);
echo $json;
$obj = json_decode($json);
print $obj->{'id'};
?>

Here is the JSON: {"data":[{"name":"Sinan \u00d6zcan","id":"610914868"}]}

It echos the JSON but I was unable to print the id.

Also I tried:

<?php
$obj = json_decode($json);
$obj = $obj->{'data'};
print $obj->{'id'};
?>

a) Instead of fopen/stream_get_contents/fclose, why not use $json = file_get_contents($url);? b) Have a look at var_dump($obj), maybe it'll help. — NikiC
– NikiC, Commented Jul 22, 2010 at 12:17

kennytm · Accepted Answer · 2010-07-22 12:18:02Z

4

Note that there is an array in the JSON.

{
    "data": [   // <--
      {
        "name": "Sinan \u00d6zcan",
        "id":   "610914868"
      }
    ]           // <--
}

You could try $obj = $obj->{'data'}[0] to get the first element in that array.

answered Jul 22, 2010 at 12:18

kennytm

526k110 gold badges1.1k silver badges1k bronze badges

Sign up to request clarification or add additional context in comments.

Comments

Felix Kling · Accepted Answer · 2010-07-22 12:18:10Z

3

data is an array, so it should be:

print $obj[0]->{'id'};

answered Jul 22, 2010 at 12:18

Felix Kling

820k181 gold badges1.1k silver badges1.2k bronze badges

Comments

Tom Haigh · Accepted Answer · 2010-07-22 12:17:39Z

3

It looks like the key "data" is an array of objects, so this should work:

$obj = json_decode($json);
echo $obj->data[0]->name;

answered Jul 22, 2010 at 12:17

Tom Haigh

57.8k21 gold badges119 silver badges143 bronze badges

Comments

pr1001 · Accepted Answer · 2010-07-22 12:18:01Z

2

~~Have you tried $obj->data or $obj->id?~~

Update: Others have noted that it should be $obj->data[0]->id and so on.

PS You may not want to include your private Facebook access tokens on a public website like SO...

answered Jul 22, 2010 at 12:18

pr1001

22k18 gold badges84 silver badges127 bronze badges

Comments

cypher · Accepted Answer · 2010-07-22 12:20:23Z

1

It's a bit more complicated than that, when you get an associative array out of it:

$json = json_decode('{"data":[{"name":"Sinan \u00d6zcan","id":"610914868"}]}', true);

Then you may echo the id with:

var_dump($json['data'][0]['id']);

Without assoc, it has to be:

var_dump($json->data[0]->id);

answered Jul 22, 2010 at 12:20

cypher

7,0024 gold badges34 silver badges48 bronze badges

Collectives™ on Stack Overflow

PHP: JSON decoding problem

5 Answers 5

Comments

Comments

Comments

Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

5 Answers 5

Comments

Comments

Comments

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related