get element in array item ajax

Question

I have a function writen in ajax that return a set of value:

$.each(data.dataa, function (i,item) {
    $.each(item, function (index, dat) {
        $str+=dat;
    })

    $ulSub.append( '<li id="'+item.id +'" class="ui-widget-content">' +$str+'</li>');
});

Each item has two attribute: the id and the lastname, the value of each $str is a concatenation of the id and the lastname, but I want just the lastname not the id. I used the function item[2] but it's not working.

the result of my code is shwon as follow

What I want is just get the value of the lasname. I know that I should use item.lastname, but I want to ask if there are other methods to get the value of the lastname because the second attribute (lastname) is a variable.

In your $.each(item, check if index is the target variable's name, if it is, append the dat to the $str. Or var target = 'lastname'; //whatever it is., then $str += item[target]; — fuyushimoya
– fuyushimoya, Commented Nov 4, 2015 at 16:49
There's no "second" element in a JavaScript object. They are unordered. Can you show a sample object (not a picture of one) that includes two different "second" properties, and the HTML you'd like to see as a result? Your desired output is very unclear at the moment. — Paul Roub
– Paul Roub, Commented Nov 4, 2015 at 16:49
What do you mean with "because the second attribute (lastname) is a variable"? — Felix Kling
– Felix Kling, Commented Nov 4, 2015 at 16:51
I've edited my code and show the result of it, as you see there are 1, 3 ,4 , 6 but I want just the second element (lastname). in others case, the lastname can be changed by name , phone or any other attribute from database, so I cani't use the method of item.lastname — Majdi Taleb
– Majdi Taleb, Commented Nov 4, 2015 at 16:53
How is it decided which data to return? You must request the data somehow. — Felix Kling
– Felix Kling, Commented Nov 4, 2015 at 16:55

juvian · Accepted Answer · 2015-11-04 17:18:33Z

1

Well, your case is quite simple, you always have an object with 2 properties: id and an unknown property. As objects do not have a defined order, you can´t assume that the field you want is always in second position

One way is to iterate the keys, and pick the one that is not equal to id:

for(var key in item){ 
    if(key != 'id'){
        $str+= item[key]
    } 
}

A similar way is to pick the object keys, and filter out the id one, then access the object with that key:

 $str+= item[Object.keys(item).filter(function(k){return k != 'id'})[0]]

If you know the possible values of the key, another way would be:

var possibleKeys = ['lastname', 'name', 'adress', 'phonenumber']

 for(var key in item){ 
    if(possibleKeys.indexOf(key) != -1){ // if its a valid key, append the value
        $str+= item[key]
    } 
}

In your case, the first option is probably the best, but there are mutiple ways to do it

edited Nov 4, 2015 at 17:18

answered Nov 4, 2015 at 17:11

juvian

16.1k2 gold badges42 silver badges40 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

get element in array item ajax

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related