Why do I get the "Array subscript is not an integer" error?

Question

void capturat(i vec[5])

{ 

    float i; for (i=0;i<=5;i++)
    {
      printf("Dame los tiempos 5 maximo:\t");
      scanf("%f",&vec[i]);
    }
}

float imprimet(float vec[5])

{

     float i;
     for(i=0;i<5;i++)
        {
            printf("Tu tiempo es %f \n",vec[i]);
        }
}

The compiler says that I have an "array subscript is not an integer" in the functions capturat() and imprimet().

this line: void capturat(i vec[5]) is not valid, perhaps you meant: void capturat(float vec[5]) — user3629249
– user3629249, Commented Nov 16, 2015 at 16:13
for readability and understandability by us humans, only one statement per line. So this: float i; for (i=0;i<=5;i++) should be two lines. — user3629249
– user3629249, Commented Nov 16, 2015 at 16:15
when calling the system function: scanf(), always check the returned value (not the parameter value) to assure the operation was successful. In this case use: if( 1 != scanf("%f",&vec[i]) ) { perror("scanf() failed"); exit( EXIT_FAILURE ); } Where the 1 is the number of format specifiers in the format parameter — user3629249
– user3629249, Commented Nov 16, 2015 at 16:20

William Ku · Accepted Answer · 2015-11-16 00:40:02Z

2

you should use integer for your loop counter i as array subscript has to be integer

int i; 
for (i=0;i<=5;i++)
{
    printf("Dame los tiempos 5 maximo:\t");
    scanf("%f",&vec[i]);
}

answered Nov 16, 2015 at 0:40

William Ku

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1 Comment

chqrlie Over a year ago

Also warn the OP about his mistake on the loop test. The code invokes undefined behaviour.

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