Parse exception in Java

Question

I am getting parse exception while running the below code, Is there anything wrong in the format ?

try {
    String Resolved= "17-04-2015 03:54" ;
    Date date  = new SimpleDateFormat("dd-MM-yyyy HH:mm:ss z").parse(Resolved);
} catch (ParseException e) {
    // TODO Auto-generated catch block
    e.printStackTrace();
}

I dont see seconds and a timezone specifier?

Caramiriel
– Caramiriel

2015-12-01 13:03:52 +00:00
Commented Dec 1, 2015 at 13:03 — Caramiriel
– Caramiriel, Commented Dec 1, 2015 at 13:03

ParkerHalo · Accepted Answer · 2015-12-01 13:05:09Z

7

Your format string is: "dd-MM-yyyy HH:mm:ss z".

z represents the timezone. You don't have a timezone in the string you try to parse: "17-04-2015 03:54". (And you don't have seconds).

Change your format string to: "dd-MM-yyyy HH:mm" and you should be fine!

answered Dec 1, 2015 at 13:05

ParkerHalo

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Comments

Naman · Accepted Answer · 2015-12-01 13:17:21Z

1

For your case, change

Date date  = new SimpleDateFormat("dd-MM-yyyy HH:mm:ss z").parse(Resolved);

to

Date date  = new SimpleDateFormat("dd-MM-yyyy HH:mm").parse(Resolved);

answered Dec 1, 2015 at 13:17

Naman

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