Short query is, in below piece of code why it's not printing found?
var products = [];
products.push("ABC", "XYZ");
var compareProducts = ["ABC","XYZ"];
console.log(products)
if($.inArray(products, compareProducts) > -1)
{
alert("found");
}
else{
alert("not found");
}
According to documentation,
The $.inArray() method is similar to JavaScript's native .indexOf() method in that it returns -1 when it doesn't find a match. If the first element within the array matches value, $.inArray() returns 0.
That's exactly how it works:
inArray: function( elem, arr, i ) {
return arr == null ? -1 : indexOf.call( arr, elem, i );
}
It finds the occurcence of your elem in arr. It does not find the occurence of obejcts of an array in another array.
If you want to check that all items in products exist in compareProducts, you may iterate over the array or use Array.prototype.every:
var products = [];
products.push("ABC", "XYZ");
var compareProducts = ["ABC","XYZ"];
if (products.every(function(x) { return $.inArray(x, compareProducts) > -1; }))
{
alert("found");
} else {
alert("not found");
}
products.every will only determine if all products are in compareProducts.The parameters to the inArray function is (String, Array) and not (Array, Array) in your case. Iterate over products and match each value using inArray
if($.inArray(products[0], compareProducts) > -1)inArray is used to find the index of any single value, not multiple values .
you are searching for an array in an array which is not meant for inArray.
$.inArray(needle, haystack);You are providing both paramerters as array.