how to copy contents of one array into another. Javascript

Question

i have a main array as

  arrayVariable = [1,2,3];

and i want another to variables to have the same content as above. If i do

anotherVariable = arrayVariable;

It will just reference that array and they wont be independent of each other. I tried this solution, but it didnt work.

 var anotherVariable = arrayVariable.slice();

Edit: Another question, while passing array through a function, does it pass the array or is it passed by reference?

like

 var array = [];
 someFunction(array);

 function someFunction(array){};

.slice() should work. Can you give an example where it doesn't? — Joseph Young
– Joseph Young, Commented Dec 22, 2015 at 10:24
does a function pass the reference of the array? question updated. — Pratish Shrestha
– Pratish Shrestha, Commented Dec 22, 2015 at 10:30

void · Accepted Answer · 2015-12-22 10:28:45Z

3

Check the below code, look they are independent.

arrayVariable = [1,2,3];
var anotherVariable = arrayVariable.slice(); // or .concat()

arrayVariable[0] = 50; // Hopefully it should not change the value of anotherVariable
alert(anotherVariable); // Look value of anotherVariable is not changed

answered Dec 22, 2015 at 10:28

void

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Theo Itzaris · Accepted Answer · 2015-12-22 10:27:32Z

0

you can try

var aa = [1,2,3,4,5,6];

var bb = [].concat(aa);//copy aa array to bb, they are now independent of each other.

hope helps.

answered Dec 22, 2015 at 10:27

Theo Itzaris

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Comments

Mathews Mathai · Accepted Answer · 2015-12-22 10:31:33Z

0

You can do it using a loop.

arrayvariable=[1,2,3];
for (var i=0;i<arrayvariable l.length;i++)
//while could also be used.
{ 

    anothervariable[i]=arrayvariable[i];
}

answered Dec 22, 2015 at 10:31

Mathews Mathai

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