NodeJS JSON.parse throwing error

Question

I am simply using JSON.parse in node.js for a array of hexadecimal id

'["5682940386289d593130ed98","568293fe86289d593130ed97","568293f486289d593130ed96"]'

getting an error,

SyntaxError: Unexpected token ' .

Even when i try passing the array as :

'[5682940386289d593130ed98,568293fe86289d593130ed97,568293f486289d593130ed96]'

it throws the error ,

SyntaxError: Unexpected token d .

weird behaviour to understand. Anybody suggestion about where I can read about the same.

Check the typeof values which you are attempting to parse. It must be string representation of the json — Rayon
– Rayon, Commented Jan 7, 2016 at 8:13
The first stringified array you gave should pass JSON.parse without error and results in an array. Is that indeed your full string you were parsing in your codebase? — TaoPR
– TaoPR, Commented Jan 7, 2016 at 8:16
@Tao P. Rr : my question is not for front-end javascript , I specifically mention it is for nodeJs you can check the below answer for details. — Prateek
– Prateek, Commented Jan 7, 2016 at 10:27

Shanoor · Accepted Answer · 2016-01-07 14:29:51Z

2

Your string starts and ends with a ' for some reason, it actually looks like this:

// run this snippet
// to see the error
var str = '\'["5682940386289d593130ed98","568293fe86289d593130ed97","568293f486289d593130ed96"]\'';
try {
  JSON.parse(str);
} catch (err) {
  console.log(err);
  snippet.log(err.stack);
}

<script src="https://tjcrowder.github.io/simple-snippets-console/snippet.js"></script>

I don't know how you build/get this string but you could strip the ending and starting ' from it by using the following code:

var str = '\'["5682940386289d593130ed98","568293fe86289d593130ed97","568293f486289d593130ed96"]\'';
str = str.replace(/^'|'$/g, ''); // remove ' before parsing
var obj = JSON.parse(str);
snippet.log(JSON.stringify(obj));

<script src="https://tjcrowder.github.io/simple-snippets-console/snippet.js"></script>

edited Jan 7, 2016 at 14:29

answered Jan 7, 2016 at 8:27

Shanoor

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2 Comments

user663031 Over a year ago

replace(/^'|'$/g, '')

Shanoor Over a year ago

@torazaburo Thanks, I forgot about these anchors.

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