Is there a shorter way to write this?
var ttt = "dd";
if (ttt.length < 3)
ttt= "i" + ttt;
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It would pay to note that all the answers here are longer and less obvious than the original code. While it can be done, I definitely wouldn't suggest you do (for the sake of those reading the code later).Aidan Kane– Aidan Kane2010-08-19 11:16:46 +00:00Commented Aug 19, 2010 at 11:16
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@Aidan: i cannot see how "var ttt="idd";" is longer and less obvious... .Davy Meers– Davy Meers2010-08-19 11:29:07 +00:00Commented Aug 19, 2010 at 11:29
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@davyM... I'll give you that one but only on a literal level.Aidan Kane– Aidan Kane2010-08-19 16:41:38 +00:00Commented Aug 19, 2010 at 16:41
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5 Answers
Yours is pretty short, but if you want to use the the conditional operator (a.k.a the ternary operator), you could do the following:
var ttt = "dd";
ttt = ttt.length < 3 ? "i" + ttt : ttt;
... or if bytes are really precious (code golfing?), you could also do something like this:
var ttt = "dd".length < 3 ? "i" + "dd" : "dd";
... but then that could be reduced to just:
var ttt = "idd";
... as @Nick Craver suggested in a comment below.
3 Comments
Nick Craver
+1 - I dunno though....
var ttt = "idd"; seems pretty short ;) Also, you need quotes around the i to be 100% on this one ;)
Daniel Vassallo
@Nick Fixed: Thought it was a variable at first.
Nick Craver
A+++++++ would do business again
The shortest with the same result is:
var ttt="idd";
because "dd" has a length of 2. so the if is always true and you'll always prepend "i"
Comments
Another option is to use a regex:
var ttt = "dd".replace(/^(\w?\w?)$/, 'i$1');
But then you have 2 problems :)
Comments
Or :
var ttt = "dd";
ttt = (ttt.length < 3 ? i : "") + ttt;
Comments
Also there's a way with && operator instead of if
var ttt = "dd";
ttt.length < 3 && (ttt = "i" + ttt);
