grep user name in unix

Question

I want to grep the username. the command id gives the following.
id output is
uid=0(root) gid=0(root)

but i want the output as only root or who ever the user is.

unwind · Accepted Answer · 2010-09-15 12:28:08Z

1

That's not a grep, that's a cut:

$ id | cut -d '(' -f 2 | cut -d ')' -f 1

If you're doing this in a script (as a comment implies), you need to capture the output of the command properly. In bash, use:

USER=$(id | cut -d '(' -f 2 | cut -d ')' -f 1)

Many o(th|ld)er shells support the backtick syntax:

USER=`id | cut -d '(' -f 2 | cut -d ')' -f 1`

answered Sep 15, 2010 at 11:17

unwind

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1 Comment

when i use it in a script , it displays nothing #!/bin/bash Userid=id | cut -d '(' -f 2 | cut -d ')' -f 1 echo $Userid

Diomidis Spinellis · Accepted Answer · 2010-09-15 11:26:58Z

0

id -un

will directly print the name associated with the current effective user-id.

answered Sep 15, 2010 at 11:26

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it stays illegal option --u . im using solaris