Python meta/unpacking in a function

Question

I have a function (func1) that returns a 4-tuple of mixed strings and integers. I want to immediately pass these 4 values into a second function (func2). This is how I am doing it now:

var1, var2, var3, var4 = func1(input1)
func2(var1, var2, var3, var4)

Functions don't unpack tuples when given as input, so this code is broken:

func2(func1(input1))

Is there a pythonic way to implement this code in the style of the second code block so func2 will unpack the values or some equivalent?

func2(*func1(input1))?

vaultah
– vaultah

2016-07-08 12:30:04 +00:00
Commented Jul 8, 2016 at 12:30 — vaultah
– vaultah, Commented Jul 8, 2016 at 12:30

Community · Accepted Answer · 2017-05-23 10:28:52Z

4

Use the * operator:

func2(*func1(input1))

edited May 23, 2017 at 10:28

CommunityBot

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answered Jul 8, 2016 at 12:30

shx2

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