PHP class variable not assigned

Question

I am having a strange issue with my php code. This is the php version I am using PHP 5.3.2-1ubuntu4.30 with Suhosin-Patch.

The issue I am having is that I cannot assign an anything to a variable that is part of my class

namespace Stats\POTSPortStats;


use PDO;
use Stats\Port;
use Stats\POTSPortStats\IPHosts\IPHosts;

class PortStats extends Port
{

    public $vcPortOnHookStatus;
    public $vcPortImpedance;
    public $ipHosts;

    /**
     * @param $secretValue int
     * @param $pdo_conn PDO
     * @return PortStats[]
     */
    public static function getAll($secretValue, $pdo_conn){
        try {
            $query =
                "SELECT * FROM secretTable WHERE secretColumn = :secretValue";
            $pdo_stmt = $pdo_conn->prepare($query);
            $pdo_stmt->bindValue(":secretValue", $secretValue, PDO::PARAM_INT);
            $pdo_stmt->execute();

            /** @var PortStats $result */ //This works right
            $result = $pdo_stmt->fetchAll(PDO::FETCH_CLASS, __CLASS__);

            //other is assigned an Array of IPHosts classes
            $other = IPHosts::getAll($secretValue, $pdo_conn);
            echo json_encode($other);
            //Checked for result, it is there.
            $result->ipHosts = $other;

            //Check just assigned value
            var_dump($result->ipHosts);
            //Value was NULL
        } catch (\PDOException $e) {
            //nothing here
            var_dump($e);
        }
        //The rest of the result is returned correctly
        return $result;
    }

Is there something wrong with my code that I am overlooking? Is there some kind of bug inside of this version of PHP that I did not find when I looked? Any help would be much appreciated. Please ask if you need more clarification.

Any errors showing? More importantly is error reporting enabled? — Script47
– Script47, Commented Jul 11, 2016 at 13:43
Ensure that PHP is set to display all errors: ini_set('display_errors', '1'); and error_reporting(E_ALL);. — Tom Wright
– Tom Wright, Commented Jul 11, 2016 at 13:45
If you are trying to change a database value like that, it won't work. You need to use UPDATE. Also remember your variables are non-static yet your function is static. — Script47
– Script47, Commented Jul 11, 2016 at 13:45

Gregor Mohorko · Accepted Answer · 2016-07-11 13:49:22Z

4

I think the problem is in this line:

$result = $pdo_stmt->fetchAll(PDO::FETCH_CLASS, __CLASS__);

Are you sure that pdo_stmt->fetchAll(...) returns an object of type PortStats? I don't think it does. It returns an array. And even more so, I don't think you can implicitly cast to class PortStats.

Try:

$results=$pdo_stmt->fetchAll(PDO::FETCH_CLASS, __CLASS__);
foreach($results as $result){
    var_dump($result);
}

answered Jul 11, 2016 at 13:49

Gregor Mohorko

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4 Comments

Adam Forbis Over a year ago

This is what I was thinking I haven't had the chance to test it yet though

Adam Forbis Over a year ago

I haven't tested it yet, but I am pretty confident that this is what the problem was, It is amazing how it is possible to miss these kind of things, and see it like a minute after you post it.

Adam Forbis Over a year ago

It should have been /** @var PortStats[] $result */ and then change some code in the IPHosts class

Adam Forbis Over a year ago

@DreamBlob OK everything works now, Spent 2 hours staring at that code. Thanks for the help!

Tom Wright · Accepted Answer · 2016-07-11 13:51:17Z

0

I think there might be an issue on the following line.

$other = IPHosts::getAll($nCircuitStatsID, $pdo_conn);

I can't see $nCircuitStatsID being defined anywhere else in your code. Is it a global?

I would also expect fetchAll() to return an array of type __CLASS__ rather than an instance of __CLASS__.

answered Jul 11, 2016 at 13:51

Tom Wright

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2 Comments

Adam Forbis Over a year ago

That is the same as $secretValue, forgot to change it.

Tom Wright Over a year ago

In that case, I expect the problem is the same as @DreamBlob outlined.

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