GSON to parse a JSON array

Question

I have a JSON file like this:

[
  {
    "id": "1",
    "name": "test1",
    "childrens": [
      {
        "id": "14",
        "name": "test2",
        "childrens": [

        ]
      }
    ]
  }
]

The model class:

public class Model {

   private int id;
   private String name;
}

And my parse method:

public List< Model > parseJSONService(JSONArray jsonArray) {

    Gson gson = new Gson();
    Model[] model = gson.fromJson(jsonArray.toString(),
            Model[].class);
    return Arrays.asList(model);
}

What are you looking for?

rajadilipkolli
– rajadilipkolli

2016-07-18 16:14:26 +00:00
Commented Jul 18, 2016 at 16:14 — rajadilipkolli
– rajadilipkolli, Commented Jul 18, 2016 at 16:14
how to build model class?

Roma Darvish
– Roma Darvish

2016-07-19 06:14:29 +00:00
Commented Jul 19, 2016 at 6:14 — Roma Darvish
– Roma Darvish, Commented Jul 19, 2016 at 6:14

Community · Accepted Answer · 2017-05-23 11:51:29Z

1

why not parse the json string directly? this is what i did, achieved the same thing you looking for i guess:

public class GsonPlay {


    public static void main(String args[]) {

        String testString = "[{\"id\": \"1\",\"name\": \"test1\",\"childrens\": [{\"id\": \"14\",\"name\": \"test2\",\"childrens\": []}]}]";
        List<Model> modelList = parseJsonService(testString);
        System.out.println(modelList);
    }

    private static List<Model> parseJsonService(String testString) {
        Gson gson = new Gson();
        Model[] models = gson.fromJson(testString, Model[].class);
        return Arrays.asList(models);
    }
}
class Model {
    private int id;
    private String name;
    private List<Model> childrens;

    public int getId() {
        return id;
    }

    public void setId(int id) {
        this.id = id;
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public List<Model> getChildrens() {
        return childrens;
    }

    public void setChildrens(List<Model> childrens) {
        this.childrens = childrens;
    }
}

You can also have a look at this for further ideas:

edited May 23, 2017 at 11:51

CommunityBot

11 silver badge

answered Jul 19, 2016 at 6:57

Mosd

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2 Comments

DerMike Over a year ago

Correct. I'm a bit concerned with childrens, though ;)

Mosd Over a year ago

yah children seem more English, developers again at it... :)

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