Couldn't run the python application based on TKinter

Question

import Tkinter as tk
from functools import partial

pad = [[1, 2, 3], [4, 5, 6], [7, 8, 9], ["C", 0, "S"]]
passcode = ""

def append_passcode(value):
    global passcode
    if len(passcode) == 4:
        passcode = passcode[1:]
    passcode += value

def clear():
    global passcode
    passcode = ""

def submit():
    global passcode
    if passcode == "1234":
        msgBox.showinfo("Login Attempt", "Successful")
        passcode = ""
    else:
        msgBox.showinfo("Login Attempt", "Failed")
        passcode = ""

main_window = tk.Tk()

btns = []
row_placement = 0
for line in pad:
    col_placement = 0
    for number in line:
        btn_command = partial(append_passcode, str(number))
        btn = tk.Button(main_window, text=str(number), width=10, command=btn_command)
        btns.append(btn)
        btn.grid(row=row_placement, column=col_placement)
        col_placement += 1
    row_placement += 1

#Setting C to clear the passcode function
btns[-3].config(command=clear)

#Setting S to submit passcode
btns[-1].config(command=submit)

I'm writing an numpad application where user must enter the correct 4 digit code to access application. when the test code runs, the GUI does not appear. What needs to be done to get this code to function?

If my answer help you, could you please press the green tick — Jonty Morris
– Jonty Morris, Commented Jul 19, 2016 at 3:40

Jonty Morris · Accepted Answer · 2016-07-19 03:00:30Z

1

Here's what you've done wrong:

Misspelled tkinter
Not included
```
main_window.mainloop()
```

Try this code

import tkinter as tk
from functools import partial

pad = [[1, 2, 3], [4, 5, 6], [7, 8, 9], ["C", 0, "S"]]
passcode = ""

def append_passcode(value):
    global passcode
    if len(passcode) == 4:
        passcode = passcode[1:]
    passcode += value

def clear():
    global passcode
    passcode = ""

def submit():
    global passcode
    if passcode == "1234":
        msgBox.showinfo("Login Attempt", "Successful")
        passcode = ""
    else:
        msgBox.showinfo("Login Attempt", "Failed")
        passcode = ""

main_window = tk.Tk()

btns = []
row_placement = 0
for line in pad:
    col_placement = 0
    for number in line:
        btn_command = partial(append_passcode, str(number))
        btn = tk.Button(main_window, text=str(number), width=10, command=btn_command)
        btns.append(btn)
        btn.grid(row=row_placement, column=col_placement)
        col_placement += 1
    row_placement += 1

#Setting C to clear the passcode function
btns[-3].config(command=clear)

#Setting S to submit passcode
btns[-1].config(command=submit)

main_window.mainloop()

Now your window should appear.

Hope this helps and feel free to comment any questions.

answered Jul 19, 2016 at 3:00

Jonty Morris

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1 Comment

Delioth Over a year ago

tkinter may not be misspelled- they have the correct spelling for python2.

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