setTimeout loop inside setInterval

Question

I have code similar to this:

var count = 0;

setInterval(function() {
  if(count===0){
    console.log(123);
    count++;
  } else if(count>0) {
    for(i=1;i<=2;i++){
        (function(ind) {
            setTimeout(function() {
              console.log(ind);
            }, 1000 * ind);
        })(i);
    }
    count=0;
  }
},1000)

The result is not what I expected, what I'd like to achieve for the console log is like:

and so on for each interval with 1000ms. Also I'd like to ask is there a better way to do this? The number of setTimeout loop(2 for the above case) can/might be different each time.

"...and so on for each interval with 1000ms..." Your inner setTimeout will sometimes be longer than 1000ms. What then? — T.J. Crowder
– T.J. Crowder, Commented Aug 4, 2016 at 8:32
something like this, first print 123 and wait for 1000ms, then 1 and wait for 1000ms, finally 2 and wait for 1000ms after that repeat the whole process infinitely — Lim SY
– Lim SY, Commented Aug 4, 2016 at 8:36
@T.J.Crowder Sorry my bad, wasn't paying attention. Will remove my comments since they are not contributing to the solution. — Michelangelo
– Michelangelo, Commented Aug 4, 2016 at 8:52

T.J. Crowder · Accepted Answer · 2016-08-04 08:39:18Z

1

something like this, first print 123 and wait for 1000ms, then 1 and wait for 1000ms, finally 2 and wait for 1000ms after that repeat the whole process infinitely

If you want it regularly at 1000ms intervals, with an inner countdown then reset, you can just use a single setInterval:

// Uses a 100ms rather than 1000ms counter, stopping after two seconds
var count = 0;
var inner = 0;
var handle = setInterval(function() {
  if (inner == 0) {
    // Start again
    console.log(123);
    count = 0;
    // The number of "inner" counts to do
    inner = 2;
  } else {
    // An "inner" count
    ++count;
    --inner;
    console.log(count);
  }
}, 100);

// Stop it after two seconds, just for demo purposes
setTimeout(function() {
  clearInterval(handle);
}, 2000);

answered Aug 4, 2016 at 8:39

T.J. Crowder

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