I am trying to find if an element exists in Array with a name.
Couldn't figure out, how to achieve the same
let string = [{"plugin":[""]}, {"test": "123"}]
console.log(string);
console.log(string instanceof Array); //true
console.log("plugin" in string); //false
plugin is not defined directly in the array, it is defined inside the object in the array.
Use the Array#find to check if any element in the array contain the given property.
array.find(o => o.hasOwnProperty('plugin'))
Use hasOwnProperty to check if object is having property.
let array = [{"plugin":[""]}, {"test": "123"}];
let res = array.find(o => o.hasOwnProperty('plugin'));
console.log(res);As an option, you can also use Array#filter.
array.filter(o => o.hasOwnProperty('plugin')).length > 0;
let array = [{"plugin":[""]}, {"test": "123"}];
let containsPlugin = array.filter(o => o.hasOwnProperty('plugin')).length > 0;
console.log(containsPlugin);You can use Array#some() and Object.keys() and return true/false if object with specific key exists in array.
let string = [{"plugin":[""]}, {"test": "123"}];
var result = string.some(o => Object.keys(o).indexOf('plugin') != -1);
console.log(result)take a look at following example code as a general answer for finding an element in an array in Javasript:
var power = [
"Superman",
"Wonder Woman",
"Batman"
];
for (var i = 0; i < power.length && power[i] !== "Wonder Woman"; i++) {
// No internal logic is necessary.
}
var rank = i + 1;
// Outputs: "Wonder Woman's rank is 2"
console.log("Wonder Woman's rank is " + rank);
I hope it can help you.
use like this
let array = [{"plugin":[""]}, {"test": "123"}];
array.find(o => o.plugin).length
