I know that if there is an array of values it must be used this approach:
console.log(['joe', 'jane', 'mary'].includes('jane')); // true
But in case of an array of arrays, is there a short way to do it? Without other computations between.
For this input:
[['jane'],['joe'],['mary']]
You can use flat method to flatten the array. For more neted array, you can also mention depth like flat(depth)
let arr = [["jane"],["joe"],["mary"]];
arr.flat().includes('jane'); //true
You can easily achieve this result using some
arr.some((a) => a.includes("jane"))
const arr = [
["jane"],
["joe"],
["mary"]
];
const arr2 = [
["joe"],
["mary"]
];
console.log(arr.some((a) => a.includes("jane")));
console.log(arr2.some((a) => a.includes("jane")));it can also be done by first flattening the 2d arrays in 1 d aaray and then using includes to find whether the array contains the element or not
var arr = [['jane'],['joe'],['marry']]
var newarr=[].concat(...arr)
var v=newarr.includes('jane')
console.log(v)
arr.some((a) => a.includes("jane"));