Extract part of a path in batch script

Question

I have a batch script with input say /home/home1/home2/home3/

I need to extract part of the file path say /home2/home3. How can I achieve this?

Thanks for the help!

How do you specify which part of the string supplied you require? — Magoo
– Magoo, Commented Sep 26, 2016 at 9:25
This is a possible duplicate stackoverflow.com/questions/1707058/… check it out! — user5196031
– user5196031, Commented Sep 26, 2016 at 9:26

npocmaka · Accepted Answer · 2016-09-26 09:43:49Z

1

Not tested:

@echo off

set "p=/home/home1/home2/home3/"
set "p=%p:/=";"%"

setlocal ENABLEDELAYEDEXPANSION
for %%a in ("%p%") do (
    if "%%~a" neq "" set "butlast=!last!"
    if "%%~a" neq "" set "last=%%~a"

)

echo %butlast%/%last%

answered Sep 26, 2016 at 9:43

npocmaka

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Comments

Rob Biggs · Accepted Answer · 2016-09-26 18:33:36Z

0

for /f "tokens=1-4 delims=/" %%a in ('echo /home/home1/home2/home3/') do @echo /%%b/%%c

tokens tells for how many variables to spit out & delims tells it what to split on. %%a is the first token, it will count out a through d because it is told to generate 4.

you will likely have your path as a variable, you can just put it in place of the path in the example, but you may need to use delayed expansion

answered Sep 26, 2016 at 18:33

Rob Biggs

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