C++ How to convert char pointer array to string array?

Question

In a C++ application, the arguments are all stored in a char* array, like so:

int main(int argc, char* argv[])
{
    ...
}

However, a lot of people prefer the convenience of string manipulation, but it would be a hastle to have to convert every char* into a std::string every time. So my question is, how do convert a char*[] into a std::string[], so that you don't have to convert them all individually as you progress in your program?

Read the chapter on loops.

Carey Gregory
– Carey Gregory

2016-10-03 03:53:54 +00:00
Commented Oct 3, 2016 at 3:53 — Carey Gregory
– Carey Gregory, Commented Oct 3, 2016 at 3:53

score 6 · Accepted Answer · 2016-10-03 04:03:36Z

6

If you accept std::vector, you can use its range constructor.

std::vector<std::string> args(argv, argv + argc);

edited Oct 3, 2016 at 4:03

answered Oct 3, 2016 at 3:56

user2486888

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2 Comments

woolstar Over a year ago

That would be a std::vector<std::string> args(...)

user2486888 Over a year ago

@woolstar Edited. Thanks.

user3196144 · Accepted Answer · 2016-10-03 04:06:43Z

1

You can loop through the arguments.

int main(int argc, char* argv[]) {

   std::string *s = new std::string[argc];
    for (int i = 0; i < argc; ++i)
        s[i] = argv[i];

}

answered Oct 3, 2016 at 4:06

user3196144

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