pass several parameters in Django rest Framework

Question

I am new with Django and Django rest framework, I try to create several routes to get the data from the database.

Right now in my urls.py file I have this

router = routers.DefaultRouter()
router.register(r'cpuProjects', cpuProjectsViewSet, base_name='cpuProjects'),

this return this

"cpuProjects": "http://127.0.0.1:8000/cpuProjects/"

and I have the possibility to do this http://127.0.0.1:8000/cpuProjects/ => return all project http://127.0.0.1:8000/cpuProjects/ad => return a particular project.

In my view.py I have this

class cpuProjectsViewSet(viewsets.ViewSet):
  serializer_class = serializers.cpuProjectsSerializer
  # lookup_field = 'project_name'
  lookup_url_kwarg = 'project_name'

  def list(self, request):
    all_rows = connect_database()
    serializer = serializers.cpuProjectsSerializer(instance=all_rows, many=True)
    return Response(serializer.data)

  def retrieve(self, request, project_name=None):
    try:
      opc = {'name_proj' : project_name }
      all_rows = connect_database(opc)
    except KeyError:
        return Response(status=status.HTTP_404_NOT_FOUND)
    except ValueError:
        return Response(status=status.HTTP_400_BAD_REQUEST)
    serializer = serializers.cpuProjectsSerializer(instance=all_rows, many=True)
    return Response(serializer.data)

Now I want that my Url accepted something like that

http://127.0.0.1:8000/cpuProjects/ad/comments http://127.0.0.1:8000/cpuProjects/ad/ussing http://127.0.0.1:8000/cpuProjects/ad/process

For this I add this new url

router.register(r'cpuProjects/([a-zA-Z0-9]+)$', cpuProjectsViewSet, base_name='cpuProjects'),

but now when I try this

http://127.0.0.1:8000/cpuProjects/ad/ussing

I obtain "page no found"

I understood that this URL have to call to retrieve function to get the parameters, so, why this error?

This URL don't do the same process like

http://127.0.0.1:8000/cpuProjects/ad

Thanks in advance!

Community · Accepted Answer · 2017-05-23 10:34:08Z

1

This is somewhat similar to what we did in our earlier Q&A

from rest_framework.decorators import detail_route, list_route
@detail_route(url_path='(?P<slug>[\w-]+)/(?P<what>[\w-]+)')
def get_by_name(self, request, pk=None,slug=None, what=None):
    print(slug, what)

Similarly you can do the same for a list_route

edited May 23, 2017 at 10:34

CommunityBot

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answered Oct 4, 2016 at 23:47

e4c5

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Comments

idik · Accepted Answer · 2016-10-03 14:23:20Z

0

The routers framework isn't meant to be used with several parameters .. you can manually do it with primary keys (in the regular expressions).

answered Oct 3, 2016 at 14:23

idik

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