Grep in Shell to extract a line from specific string

Question

I have a file with below text

^[[8mha:AAAAYB+LCAAAAAAAAP9b85aBtbiIQSmjNKU4P0+vJLE4u1gvPjexLDVPzxdEuhYV5Rf55ZekOlc7RKnPKH7IxMBQUcQgBdWQnJ9XnJ+TqucMoUEKGSCAEaSwAACsNFCqYAAAAA==^[[0m[ERROR] ^[[8mha:AAAAYB+LCAAAAAAAAP9b85aBtbiIQSmjNKU4P0+vJLE4u1gvPjexLDVPzxdEuhYV5Rf55ZekOlc7RKnPKH7IxMBQUcQgBdWQnJ9XnJ+TqucMoUEKGSCAEaSwAACsNFCqYAAAAA==^[[0m[ERROR] /opt/app/ElectronicTransactionVOtoDOMapper.java:[1060,1] error: reached end of file while parsing ^[[8mha:AAAAYB+LCAAAAAAAAP9b85aBtbiIQSmjNKU4P0+vJLE4u1gvPjexLDVPzxdEuhYV5Rf55ZekOlc7RKnPKH7IxMBQUcQgBdWQnJ9XnJ+TqucMoUEKGSCAEaSwAACsNFCqYAAAAA==^[[0m[ERROR] -> [Help 1] ^[[8mha:AAAAYB+LCAAAAAAAAP9b85aBtbiIQSmjNKU4P0+vJLE4u1gvPjexLDVPzxdEuhYV5Rf55ZekOlc7RKnPKH7IxMBQUcQgBdWQnJ9XnJ+TqucMoUEKGSCAEaSwAACsNFCqYAAAAA==^[[0m[ERROR] ^[[8mha:AAAAYB+LCAAAAAAAAP9b85aBtbiIQSmjNKU4P0+vJLE4u1gvPjexLDVPzxdEuhYV5Rf55ZekOlc7RKnPKH7IxMBQUcQgBdWQnJ9XnJ+TqucMoUEKGSCAEaSwAACsNFCqYAAAAA==^[[0m[ERROR] To see the full stack trace of the errors, re-run Maven with the -e switch

from the above log, I have to extract only the below:

[ERROR]
[ERROR] /opt/app/ElectronicTransactionVOtoDOMapper.java:[1060,1] error: reached end of file while parsing
[ERROR] -> [Help 1]
[ERROR]
[ERROR] To see the full stack trace of the errors, re-run Maven with the -e switch

Eventually, I should not get the Junk value in the log instead I need a clear Error message.

Could you please help me in getting the right command in shell?

I derived this.. cat -v log_10-29-2016_04_12 | grep -o '[ERROR.*' but not sure that the command works in all scenarios. — Sakthisiga
– Sakthisiga, Commented Oct 29, 2016 at 8:15

Cwissy · Accepted Answer · 2016-10-29 09:34:28Z

1

probably should use sed rather than grep here.

sed -n '/ERROR/s/.*\(\[ERROR\].*\)$/\1/p' log_10-29-2016_04_12

gets only lines containing the word 'ERROR' and strips everything from the left of the '[ERROR]' and prints the rest.

answered Oct 29, 2016 at 9:34

Cwissy

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zxy · Accepted Answer · 2016-10-29 13:16:53Z

0

awk -vRS='^' -F "] " '/ERROR/{print "[ERROR] "$2}' file

answered Oct 29, 2016 at 13:16

zxy

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1 Comment

Scott Weldon Over a year ago

While this code snippet may solve the problem, it doesn't explain why or how it answers the question. Please include an explanation for your code, as that really helps to improve the quality of your post. Remember that you are answering the question for readers in the future, and those people might not know the reasons for your code suggestion. Flaggers / reviewers: For code-only answers such as this one, downvote, don't delete!

VIPIN KUMAR · Accepted Answer · 2016-10-29 18:45:42Z

0

Try below grep command to achieve the output -

vipin@kali:~$ grep "\[ERROR\]" kk.txt |cut -c6-
[ERROR]
[ERROR] /opt/app/ElectronicTransactionVOtoDOMapper.java:[1060,1] error: reached end of file while parsing
[ERROR] -> [Help 1]
[ERROR]
[ERROR] To see the full stack trace of the errors, re-run Maven with the -e switch

explanation : \[ and \] for escaping and -c6- to print after 6th character till end of line.

answered Oct 29, 2016 at 18:45

VIPIN KUMAR

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