Explode string from database and show result in function

Question

I have this query and function

$images = [];
$q = $pdo->query("SELECT * FROM projects ORDER BY project_id ASC LIMIT 8");
foreach($q as $row)  {

        $mainTitle1 = $row['project_category'];
        $parts1=explode(" ",$mainTitle1);

        $images[] = [
             'project_category' => $row['project_category'],
             'project_id'    => $row['project_id'],
             'project_image'    => $row['project_image']          
        ];
}
function image_html($image) {
        return '<img src="'.$image['project_image'].'" alt="">';
}
function category($category) {
        return '<span class="item-title">'.$parts1[0].'</span><span class="item-cat"> '.$parts1[1].'</span> ';
}

Which then I'm trying to display like this

<div class="itemm web">
    <?php echo image_html($images[0]); ?>
            <div class="item-overlay">
                <?php echo category($images[0]); ?>             
            </div> 
</div> 
<div class="itemm w_60 web">
    <?php echo image_html($images[1]); ?>
            <div class="item-overlay">
                    <?php echo category($images[1]); ?>
            </div> 
</div>

<?php echo image_html($images[0]); ?> is showed correctly on the page but <?php echo category($images[0]); ?> it isn't. It's empty.

In database I have Name subname the idea is to show Name <span class="item-title">'.$parts1[0].'</span> and subname on <span class="item-cat"> '.$parts1[1].'</span>'

Why doesn't show anything?

$category not equal to $parts1

devpro
– devpro

2016-10-31 12:30:29 +00:00
Commented Oct 31, 2016 at 12:30 — devpro
– devpro, Commented Oct 31, 2016 at 12:30

devpro · Accepted Answer · 2016-10-31 12:41:44Z

2

Note that, in category() variable $category is not equal to $parts1.

You are using wrong or undefined variable $parts1 in the body of category() method.

Update:

As per you comment, if you want to access $parts1 inside the category method, than you must need to pass $parts1 as a function param something like:

function category($image,$parts1){}

Otherwise you can't access the $parts1 just because of variable scope issue.

The most important thing is that, $parts1=explode(" ",$mainTitle1); will only return the last record in an array means it will contain only one record.

But, as per body of category() method, you are not using $image here, so you can only pass $parts1 in this method.

edited Oct 31, 2016 at 12:41

answered Oct 31, 2016 at 12:31

devpro

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13 Comments

Jason Paddle Over a year ago

But I have $parts1 in the foreach where I explode project_category

devpro Over a year ago

@JasonPaddle: chk my update, you need to use $parts1 in function param

Jason Paddle Over a year ago

It's make a bit more sense but I've got Missing argument 2 for category()

devpro Over a year ago

@JasonPaddle: u also need to pass second param where you are calling it.

Jason Paddle Over a year ago

Okay, is that meaning that it wont work as I need it like this?

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