Sorting 2d string array with integer

Question

i created a 2d string array (called data) which contains on the first position an integer (as a string) and on the second position a link to a file.

Examples:

["3", "Test3.pdf"]; ["1", "Test1.pdf"];  ["2", "Test2.pdf"];  ["10", "Test10.pdf"]

So now I need to sort the array ascending for the integer. So the result of the sorting should be an sorted array like:

["1", "Test1.pdf"];  ["2", "Test2.pdf"];["3", "Test3.pdf"];["10", "Test10.pdf"]

I found some sample code for this:

Arrays.sort(data, new Comparator<String[]>() {
    @Override
    public int compare(final String[] entry1, final String[] entry2) {
        final String time1 = entry1[0];
        final String time2 = entry2[0];
        return time1.compareTo(time2);
    }
});

but the problem is, that in this case it compares it with string logic, so the result would be-> 1,10,2,3. So I cannot archive the result with this. Do you know what can I do? You only can have an 2d array of one type? not mix of string and integer?

Do you need to have this as an array of arrays of strings? A simple collection of objects with separate int and String parts would almost certainly be better, not just here but throughout your code. — Jon Skeet
– Jon Skeet, Commented Nov 8, 2016 at 11:10
If you need to have strings in the array, just convert to int in the compare method. — tobias_k
– tobias_k, Commented Nov 8, 2016 at 11:11
The best structure to handle your problem is TreeMap<Integer,String> — Naruto Biju Mode
– Naruto Biju Mode, Commented Nov 8, 2016 at 11:25

Jerry Chin · Accepted Answer · 2016-11-08 11:14:30Z

1

The comparison can be done by converting the first element to Integer, as demonstrated in the following snippet:

Arrays.sort(data, new Comparator<String[]>() {
    @Override
    public int compare(final String[] entry1, final String[] entry2) {
        final Integer time1 = Integer.valueOf(entry1[0]);
        final Integer time2 = Integer.valueOf(entry2[0]);
        return time1.compareTo(time2);
    }
});

answered Nov 8, 2016 at 11:14

Jerry Chin

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Comments

Massimo Petrus · Accepted Answer · 2016-11-08 11:22:36Z

0

You can do like this

    Arrays.sort(data, new Comparator<String[]>() {
    @Override
    public int compare(final String[] entry1, final String[] entry2) {
        final Integer time1 = Integer.parseInt(entry1[0]);
        final Integer time2 = Integer.parseInt(entry2[0]);
        return time1.compareTo(time2);
    }
});

answered Nov 8, 2016 at 11:22

Massimo Petrus

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2 Comments

tobias_k Over a year ago

Is this answer any different from the one posted 8 minutes earlier?

Massimo Petrus Over a year ago

basically not..i just didn't see it while I was testing it

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