Sorting 2d Integers Array Java

Question

i have an 2d Array which is [2][10]. It is filled with random numbers. Could someone please help me how to sort it? I dont know why but any found way to sort it with Comparator doesnt work for me. So im trying to do that in a loop. It has to be sorted by the column.

Im trying to play with creating a temporary array and inserting the value into it, but i dont know how to compare values: [0][0] and [0][1]. My try is do 2 for loops and inside it:

for (int i = 0; i < arr4.length; i++) {
    for(int j = 0; j < arr4[i].length; j++) {
        if(arr4[i][j] > ???????)
    temparray = arr4[i][j];
    }
 }

Help me please...

Please provide sample test case and expected output for that test case. — vicki
– vicki, Commented Oct 1, 2020 at 15:57

Azzabi Haythem · Accepted Answer · 2020-10-01 16:16:06Z

1

if you need to sort line by line you need to update your solution like this

  for (int i = 0; i < arr4.length; i++) {
        for(int j = 0; j < arr4[i].length-1; j++) {
            if(arr4[i][j] > arr4[i][j+1]){
              temparray = arr4[i][j];
              arr4[i][j] = arr4[i][j+1]
              arr4[i][j+1] = temparray  ;
              j=0;
          }
        }
     }


input:
[1.0, 2.0]
[6.0, 4.0]
[5.0, 4.0]

output:

[1.0, 2.0]
[4.0, 6.0]
[4.0, 5.0]

answered Oct 1, 2020 at 16:16

Azzabi Haythem

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