How to find an array of strings in a string?

Question

I'd like to search a string for multiple strings, and return true if it finds any of them in there, false otherwise, something like this:

var s = "thing1 thing2"
s.contains(["thing1","thing44444"]) // true
s.contains("1") // true
s.contains("x") // false

Here's what I have so far, but it's getting messier and doesn't really work:

String.prototype.contains = function(xv) {
    var t = this
    if(xv.isString()){ // isString/isArray are functions I made elsewhere in my code, they work.
        if(t.indexOf(xv) > -1)
            return true;
    } else if(xv.isArray()) {
        if(xv.contains(t)){
            return true
        }
        for(v in xv){
            if(t.indexOf(xv[v]) > -1){
                return true
            }
        }
    } else {
        return false
    }
}

As of now, it will return undefined if it makes it through the for loop without finding anything. I had return false after the for loop, but it would run before the for finished.

I feel like there's gotta be an easier way to do this.

I've already tried How do you search multiple strings with the .search() Method? but I couldn't send an array to .search().

Frameworks I'm using: angular 1.5.8, jquery 1.11.1

"I had return false after the for loop, but it would run before the for finished." this isn't possible given the code in your example. — zzzzBov
– zzzzBov, Commented Nov 8, 2016 at 20:02
You may wish to rethink altering the prototype of built in objects, or at least make sure you're polyfilling correctly. See also Why is extending native objects a bad practice?. For instance Array.isArray is already a function in recent versions of JavaScript, and Angular already has angular.isString()... — Heretic Monkey
– Heretic Monkey, Commented Nov 8, 2016 at 20:07
@MikeMcCaughan from the first answer you quoted: "Changing the behaviour of an object that will only be used by your own code is fine." I do appreciate the references though. Lots of good info here. Thanks brother. — Travis Heeter
– Travis Heeter, Commented Nov 11, 2016 at 21:09

adeneo · Accepted Answer · 2016-11-08 20:00:24Z

4

You can use Array.some and String.indexOf or String.includes

var s1 = "thing1 thing2";
var s2 = "Hello Kitty";

var r1 = ["thing1","thing44444"].some( x => s1.includes(x));
var r2 = ["Travis","Heeeeeeter"].some( x => s2.includes(x));

console.log(r1, r2); // true, false

answered Nov 8, 2016 at 20:00

adeneo

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