i would like help to convert byte to dictionnary, i have;
received message: b'req:21;num:54771377;INFO:;GATE:N;'
i would like
d1 = {'req':21,'num':54771377,'INFO':,'GATE':N}
thank you
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hello, what did you done to make this? Can you please show us some code.tanaydin– tanaydin2016-11-09 14:25:40 +00:00Commented Nov 9, 2016 at 14:25
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2 Answers
Do that with a gencomp piped into a dictionary (drop the empty fields). Split according to semicolon after having converted the bytes to string (assumption: data inside the bytes object is ASCII)
s = b"req:21;num:54771377;INFO:;GATE:N;"
d = dict(toks.split(":") for toks in s.decode("ascii").split(";") if toks)
print(d)
result:
{'INFO': '', 'GATE': 'N', 'req': '21', 'num': '54771377'}
notes:
a dictcomp would be tempting like this
d = {toks.split(":")[0] : toks.split(":")[1] for toks in s.decode("ascii").split(";") if toks}but it would mean that you split twice as too many on colonif you have non-ascii data, you can still do the job, but the data will remain as
bytes:d = dict(toks.split(b":") for toks in s.split(b";") if toks)
answered Nov 9, 2016 at 14:30
Comments
Something like this?
str = b'req:21;num:54771377;INFO:;GATE:N;'.decode("ascii")
arr = str.split(';')[::-1]
arr = [x.split(':') for x in arr if x != '']
return dict(arr)
Result:
{u'INFO': u'', u'GATE': u'N', u'num': u'54771377', u'req': u'21'}
Repl: https://repl.it/X3G/8284
