Create Dictionary with byte keys (based on strings)

Question

How can directly create a dict with byte keys in a list comprehension?

I've tried it with fstrings and a byte conversion but a shorter version would be nice.

expression:

_dict = {bytes(f"test_{_i}", encoding="utf-8"): _i for _i in range(0, 1)}

Result:

_dict = {b'test_0': 0}

Szabolcs · Accepted Answer · 2022-03-22 13:33:55Z

2

What about the str.encode method, like this:

_dict = {f"test_{_i}".encode(): _i for _i in range(0, 1)}

Note: in order to make it shorter you can skip the explicit declaration of the encoding as "utf-8", since that is the default encoding anyways.

answered Mar 22, 2022 at 13:33

Szabolcs

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Comments

Terry Spotts · Accepted Answer · 2022-03-22 14:27:38Z

2

You could use a bytes string and percent formatting:

_dict = {b"test_%d" % _i: _i for _i in range(0, 1)}
print(_dict)

Output:

{b'test_0': 0}

answered Mar 22, 2022 at 14:27

Terry Spotts

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