Add trigger to AWS Lambda Function using Java API

Question

How can I add new trigger for existing AWS Lambda function using Java API?

I would like to add CloudWatch Events - Schedule trigger.

It looks like I should use AmazonCloudWatchEventsClient. How can I set the credentials for the client?

Any examples will be appreciated.

Thanks.

stivlo · Accepted Answer · 2018-09-12 22:36:43Z

4

It is possible to add event sources via aws sdk. I faced the same issue and please see code below as the solution using java.

AddPermissionRequest addPermissionRequest = new AddPermissionRequest();
addPermissionRequest.setStatementId("12345ff");  //any unique string would go
addPermissionRequest.withSourceArn(ruleArn); //CloudWatch rule's arn
addPermissionRequest.setAction("lambda:InvokeFunction");
addPermissionRequest.setPrincipal("events.amazonaws.com");
addPermissionRequest.setFunctionName("name of your lambda function");

AWSLambdaAsyncClient lambdaClient = new AWSLambdaAsyncClient();
lambdaClient.withRegion(Regions.US_EAST_1); //region of your lambda's location

lambdaClient.addPermission(addPermissionRequest);

edited Sep 12, 2018 at 22:36

stivlo

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answered Jun 22, 2017 at 12:38

Anvita Shukla

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2 Comments

chaitanya Over a year ago

This works fine for me, but only problem is AWSLambdaAsyncClient is deprecated.

stivlo Over a year ago

@chaitanya it works also with AWSLambda client AWSLambda lambdaClient = AWSLambdaClientBuilder.defaultClient();

Blundell · Accepted Answer · 2019-03-25 16:34:52Z

0

Thanks needed it in Kotlin myself, the thing missing from the previous answer was the dependency:

compile 'com.amazonaws:aws-java-sdk-lambda:1.11.520'

code:

val addPermissionRequest = AddPermissionRequest()
addPermissionRequest.statementId = "12345ff"  //any unique string would go
addPermissionRequest.withSourceArn(ruleArn) //CloudWatch rule's arn
addPermissionRequest.action = "lambda:InvokeFunction"
addPermissionRequest.principal = "events.amazonaws.com"
addPermissionRequest.functionName = "name of your lambda function"

val lambdaClient = AWSLambdaAsyncClient.builder().build()
lambdaClient.addPermission(addPermissionRequest)

answered Mar 25, 2019 at 16:34

Blundell

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