How do i pull out the 30 or the 55 basically the number before the last number
http://something.com:9090/general/35/30/205
http://something.com:9090/general/3/55/27
http://something.com:9090/general/36/30/277
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w3schools.com/jsref/jsref_obj_regexp.aspStephen– Stephen2010-11-03 17:55:10 +00:00Commented Nov 3, 2010 at 17:55
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4 Answers
You need to use regular expressions for this. As a brief example, here you need to do the following:
var url = "http://something.com:9090/general/35/30/205";
var category = url.match(/(\d+)\/\d+$/)[1];
To parse the regular expression:
/start the regular expression(\d+)create a group that you want to find the value of later. This group must contain 1 or more number characters\/next must come a forward slash. The backslash "escapes" the forward slash -- otherwise it would end the regular expression\d+next must come 1 or more number characters$this must be the end of the string/end the regular expression.
The match function returns an array of items that we selected -- here, just (\d+). The [1] means "get the first match", which will be 30 in the above string.
6 Comments
zincorp
Ah yes, the ol' t-shirt before the t-shirt regex
lonesomeday
@zincorp I think I'm missing something.
Mike Ruhlin
If you have a problem, and you decide to solve that problem with regex, you now have two problems
MooGoo
This is the most concise solution. Perhaps regex is overkill for this but if you understand it then it does its job just fine.
lonesomeday
@Mike Ruhlin I looked at the solution you give before posting this, and it seemed to perform better. It seems that the performance advantage depends on the browser, which I didn't initially realise. I disagree that regex is inherently a problem, as you suggest.
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var url = "http://something.com:9090/general/35/30/205";
var splits = url.split('/');
return splits[splits.length - 2];
This will screw up if your url looks like: "http://something.com:9090/general/35/30/205/" but you could always trim off the trailing slashes beforehand.
Comments
var s = "http://something.com:9090/general/35/30/205";
s.substr(s.lastIndexOf('/') - 2,2);
2 Comments
lonesomeday
This will work as long as the number has precisely two digits.
/3/205 and /300/205 would both give the wrong result.var parts = url.split('/');
var i = parts.length, num;
while (--i)
if (!isNaN(parts[i]) && !isNaN(parts[i+1])) {
num = parts[i];
break;
}
Without regex, and somewhat like Mike Ruhlin's solution, but more specific to the "number before the last number" part of your question.
