Jquery add element if not found in array

Question

Using jQuery, I am trying to check if a value x exists in my array. Basically, when clicking the testButton I have a var x that starts from zero Using this value I am trying to check if in the array there is an element with value 0. If there is, increment x and perform the array scan again. This should happen until x has a value which is not found in the array. Then at this point I know that I can use this id for the element. At the moment I have this code that checks if value x is in array, but this happens only for the length of the array. Next iteration should be: x=3, x is not in array so can be used as id. Can someone help to implement this. Thanks

  var array = ["0","1","2"];
  var x = 0;

  $("#testButton").click(function(){
        $.each(array, function(index,value){
            if($.inArray(x.toString(),array == -1)){
              console.log('found item with x value in array, increment x and scan the array again');
            }
            else{
              console.log('not in array, add id to element and push current x value to array.');
            }
            x=x+1;
        });
      });

work use of inArray should be if($.inArray(x.toString(),array) >= 0){ — rafwlaz
– rafwlaz, Commented Dec 12, 2016 at 23:05
Note use care with the ["0","1","2"]; vs a possible use of [0,1,2]; — Mark Schultheiss
– Mark Schultheiss, Commented Dec 12, 2016 at 23:09
Thanks. A bit off topic, how to check for [0,1,2]. In array performs check on strings. — Otonel88
– Otonel88, Commented Dec 12, 2016 at 23:19

Mark Schultheiss · Accepted Answer · 2016-12-12 23:05:59Z

1

var a = ["0","1","2"];
a.includes("2"); // true 
a.includes("4"); // false

copied from https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/includes

answered Dec 12, 2016 at 23:05

Mark Schultheiss

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Comments

manonthemat · Accepted Answer · 2016-12-12 23:09:35Z

0

var array = ["0","1","2"];
var x = 0;

$("#testButton").click(function(){
  while(array.includes(x.toString())) x++;
});

answered Dec 12, 2016 at 23:09

manonthemat

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