laravel ajax action url with parameters

Question

I have a problem with an ajax call. The url that i need to get the data is:

localhost/public/getCode?course_id=1&task_id=1

My ajax call is:

function getCode() {
                $.ajax({
                    type: "GET",
                    dataType: 'json',
                    url: "{{action('CodeEditorController@getCode',['course_id'=>$course,'task_id'=>$maintask])}}",
                    success: function (data) {
                        console.log(data);
                    }
                });
            }

But the data returned is empty.

Edit: getCode function:

public function getCode(Request $request)
{
    $code=Code::where('user_id',$user->id)->where('main_task_id',$request->input('task_id'))->first()->code;
    $response = [
        'data' => $code
    ];

    return response()->json($response, 200);
}

What is the issue with my ajax code?

Thanks!

Any errors returned or just empty result set? Try adding error logging for ajax request after your success statement. error: function(jqXHR, textStatus, errorThrown) { $content.fadeOut(200); console.log(JSON.stringify(jqXHR)); console.log("AJAX error: " + textStatus + ' : ' + errorThrown); — Andrew Nolan
– Andrew Nolan, Commented Jan 3, 2017 at 19:32
@AndrewNolan no error, just empty response. With postman it returns the data, but with my ajax call it wont. I think its a problem with my ajax code — user3844579
– user3844579, Commented Jan 3, 2017 at 19:34
hmmm, maybe try adding your parameters as a data section in ajax call instead of attached to url. data: {'task_id' : $maintask, 'course_id' : $course} — Andrew Nolan
– Andrew Nolan, Commented Jan 3, 2017 at 19:37

Alexey Mezenin · Accepted Answer · 2017-01-03 19:55:26Z

4

One way to do that is to use data for options:

data: {
    'course_id': {{ $course }},
    'task_id': {{ $maintask }} 
},

To get values in controller you can just use request('course_id') and request('task_id')

Also it's a really bad idea to use Blade/PHP to build JS. You should use hidden inputs or something to pass data to JS.

answered Jan 3, 2017 at 19:55

Alexey Mezenin

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