How to define Laravel action function in ajax url?

Question

I'm facing problem with laravel ajax i want to define url using laravel action() or route('page.destory') function with id . Ajax code is here

$(".delete").click(function(){
var id = $(this).data("id");
var token = $("meta[name='csrf-token']").attr("content");

$.ajax(
{
    url: "{{action('Admin\Page\PageController@destroy')}}+id",
    method: 'DELETE',
    data: {
        "id": id,
        "_token": token,
    },
    success: function (data){
        alert(data);
    }
});

});

Laravel give me error Missing required parameters for [Route: page.destroy]

in web.php Route::resource('page','PageController);

How can i pass id with that action of destroy. url should be look like http://example.com/admin/page/1. but i do not want to write url manually.Many Thanks in advance.

Lukáš Irsák · Accepted Answer · 2019-02-09 17:18:26Z

1

url: "{{action('Admin\Page\PageController@destroy')}}+id",

Just guessing but I think that this line is wrong, because you are appending +id string not + variable id

So it's actually produce http://example.com/admin/page/+id which is wrong.

Try to change it like this:

url: "{{ action('Admin\Page\PageController@destroy') }}" + id

Also not sure if you need to add slash before id like this:

url: "{{ action('Admin\Page\PageController@destroy') }}/" + id

Try to open inspector in your browser and look for network tab. Try to click on that delete button and see the last request. You will see there what you are actually posting to server.

In chrome like this:

edited Feb 9, 2019 at 17:18

answered Feb 9, 2019 at 17:10

Lukáš Irsák

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1 Comment

Hashaam zahid Over a year ago

hello buddy, last question which is best way to define script in laravel . in app.js and run dev or on footer of page . what laravel recommend

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