How to change value of a vector string to a different string value?

Question

I was doing this exercise on writing a program that takes in words and prints the list of words without repetition. However, I am stuck when the question further asked to replace a word of choice(that I dislike) to "Bleep".

Here is the code:

#include <iostream>
#include <vector>
using namespace std;

int main()
{
    vector<string>words;
    string temp;

    while (cin>>temp)
        words.push_back(temp);

    cout << "Number of words: " << words.size() << "\n";

    for (int i = 0; i<words.size(); ++i)
        if(i == 0 || words[i-1] != words[i])
            cout << words[i] << '\n';



    return 0;
}

How can I add codes to change a string input by the user for example 'cute' to 'Bleep'? Thank you so much.

Just get that input word from the user, and add an if/else inside the while loop... BTW, your question kinda leaves the impression that you're asking us to do your homework for you. — barak manos
– barak manos, Commented Feb 1, 2017 at 6:46
you can use std::find if iterator return is not the end then you can use this iterator to change the value. — user1438832
– user1438832, Commented Feb 1, 2017 at 6:48
If you need list of words without repetition, u need to use set<T> instead of vector<T>. Other than that, use answer from @acraig5075 — Leontyev Georgiy
– Leontyev Georgiy, Commented Feb 1, 2017 at 7:05

acraig5075 · Accepted Answer · 2017-02-01 13:47:37Z

3

You can compare the input word with a list of prohibited words and continue according to whether the input word is in the list or not.

#include <algorithm>

vector<string> badWords = { "bad", "words", "for", "example", "cute" };

while (cin>>temp)
{
  if (std::find(badWords.begin(), badWords.end(), temp) == badWords.end())
    words.push_back(temp);
  else
    words.push_back("bleep");
}

edited Feb 1, 2017 at 13:47

answered Feb 1, 2017 at 6:56

acraig5075

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Comments

jbsu32 · Accepted Answer · 2017-02-01 07:14:51Z

1

Just Change your

while (cin>>temp)
    words.push_back(temp);

this block to the following block:

vector<string> bad_words = { "beautiful", "nice", "sweet", "cute" };  // The badwords you have
while (cin>>temp){
    for(int i=0; i<bad_words.size(); i++){
        if(bad_words[i]==temp){
            temp="bleep";
            break;
        }
    }
    words.push_back(temp);
}

answered Feb 1, 2017 at 7:14

jbsu32

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Comments

gamekoff · Accepted Answer · 2017-02-01 20:53:57Z

0

Am I right that by

prints the list of words without repetition

you mean transform your initial vector of strings to the vector of unique strings? In such a case your algorithm is wrong. Look at the part

for (int i = 0; i<words.size(); ++i)
    if(i == 0 || words[i-1] != words[i])
        cout << words[i] << '\n';

This algoritm does not handle the cases where two or more repetitions are separated. For example

input: word1 word2 word3 word1 word1 word1
output: word1 word2 word3 word1

The output vector includes two equal words.

answered Feb 1, 2017 at 20:53

gamekoff

1

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