How to display a php variable in input checkbox

Question

I made a small user database with some checkboxes in a html input form. In there I have some basic infos about the users like value 1 and 2 (among others) and some checkboxes as well (here you see one). Default is always 0, but when I click the checkbox its changes to 1.

<input type="text" placeholder="Value 1" value="<?php echo set_value('value1'); ?>" name="value1" size="6"/>
<input type="hidden" value="0" name="spec1"/><input type="checkbox" value="1" name="spec1"/>
<input type="text" placeholder="Value 2" value="<?php echo set_value('value2'); ?>" name="value2" size="6"/>

Now I would like to have a form in which I can see all these informations later on and edit it if necessary. But the checkbox I can't display properly. It is always empty. So I had to change it to a textbox. So I can see whether that specific values are 0 or 1.

<input type="text" name="Value 1" value="<?php echo $value1; ?>">
<input type="text" name="spec1" value="<?php echo $spec1; ?>">
<input type="text" name="Value 2" value="<?php echo $value2; ?>">

Is it possible somehow to show the values in a checkbox again, so I can change the type of the second line to "checkbox" again instead of "text"? Means can I display a value 1 as a checked checkbox and 0 as an empty checkbox?

to check your checkbox use the attribute 'checked' : <input type="checkbox" name="Value 1" checked> — Sir McPotato
– Sir McPotato, Commented Feb 28, 2017 at 8:34
to expand a bit: <input type='checkbox' name='someName' <?php if ($someValue==1) echo 'checked="checked"'>. this will set the checked attribute if your value matches a condition. Hope that helps? — Burki
– Burki, Commented Feb 28, 2017 at 10:32

Shafiqul Islam · Accepted Answer · 2017-02-28 08:42:27Z

check this code , you can use checkbox and check value is set and you need to show user so you checkbox level then you can use

<input type="checkbox" name="Value 1" value="<?php echo $value1; ?>"><?php echo $value1; ?>
<input type="checkbox" name="spec1" value="<?php echo $spec1; ?>"> <?php echo $spec1; ?>
<input type="checkbox" name="Value 2" value="<?php echo $value2; ?>"> <?php echo $value2; ?>

for demo test check this code also

<input type="checkbox" name="Value 1" value="1">Test1
<input type="checkbox" name="spec1" value="2"> Test2
<input type="checkbox" name="Value 2" value="3"> Test3

and if you want to checkbox checked then use also this

<?php
 $value1 = 1;
 $spec1 = 2;
 $value2 = 3;

 $compare_value = 3;
 ?>
 <input type="checkbox" name="Value 1" value="1" <?php if($value1 ==$compare_value) { echo 'checked';}?>>Test1
 <input type="checkbox" name="spec1" value="2" <?php if($spec1 ==$compare_value) { echo 'checked';}?>> Test2
 <input type="checkbox" name="Value 2" value="3" <?php if($value2 ==$compare_value) { echo 'checked';}?>> Test3

JensV · Accepted Answer · 2017-02-28 08:35:12Z

1

Checkboxes aren't checked or not by their value attribute. They have a checked attribute: https://developer.mozilla.org/en-US/docs/Web/HTML/Element/input/checkbox

So in your example:

<input type="checkbox" name="..." <?php if($value1) echo 'checked="checked"'; ?> >

answered Feb 28, 2017 at 8:35

JensV

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Comments

Mawcel · Accepted Answer · 2017-02-28 11:34:08Z

0

What checks a checkbox is the checked attribute not value

You can add that attribute depending on the value you are retrieving from your database like so:

<?php if($value == 1): ?>
   <?php echo '<input type="checkbox" checked name="spec1"/>' ?>
<?php else: ?>
   <?php echo '<input type="checkbox" name="spec1"/>' ?>
<?php endif; ?>

or for short

<input type="checkbox" <?php if(value == 1) echo 'checked'; ?> name="spec1"/>

edited Feb 28, 2017 at 11:34

answered Feb 28, 2017 at 8:36

Mawcel

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1 Comment

Didi Mike Over a year ago

THANKS to all of you guys!!!! :))) thats why i never found a solution online, because i was looking from a wrong perspective. thanks a lot, now it works fine!!!

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