Python RegEx multiple LInes

Question

I am stuck. I am trying to get rid of the tag and the whitespace between the tag using a regex.

b="<NAME> 
   content here 
   more content
</NAME>
"
result = re.sub("<NAME.*?NAME>", "", b)

If 'b' is all on one line it work. It removes everything between the name tags. But I need it to work with multiple lines as well.

Dot never matches newline unless you turn on single-line mode. — Kenneth K.
– Kenneth K., Commented Mar 22, 2017 at 15:24

Kasravnd · Accepted Answer · 2017-03-22 15:33:17Z

1

Your regular expression is not correct. You can use the following regex:

In [7]: print(re.sub(r'\s*</?NAME>\s*', '', b))
content here 
   more content

or:

In [8]: print(re.sub(r'\s*</?NAME>\s*\n', '', b))
   content here 
   more content

answered Mar 22, 2017 at 15:33

Kasravnd

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4 Comments

user3525290 Over a year ago

Thanks for your help. Maybe I did not explain myself very good. But what I am trying to accomplish is to get rid of everything between the tags and remove the tags also. The In 7 does remove the spaces and the name tags but it leaves the other characters inbetween.

user3525290 Over a year ago

This is what I have so far. I just need to combine so it is only one. re.sub(r'(.+\s*</?NAME>\s*,'',b); The above removes everything inside the name tag and the </name> tag. I made another regex to remove the first name tag re.sub(r'<name>\s*','',b). How do i combine them?

Kasravnd Over a year ago

@user3525290 So can you just add your expected output to your question?

user3525290 Over a year ago

I figured it out. The expected outcome should have been "Left over text". from b="<name> junk in here to remove </name> Left over text". What I wanted to do was remove the name tags and everything inbetween. What I came up with thanks to this help was. re.sub(r'^<name>.?</?name>') however this will only work if <name is at the beginning of the file.

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