int[] alist = new int [3];
alist.add("apple");
alist.add("banana");
alist.add("orange");
Say that I want to use the second item in the ArrayList. What is the coding in order to get the following output?
output:
banana
-
9Your code will not compile: alist it an array, but you use it like an List -- this is impossible and alist is of type integer - you are not able to assign Strings to it.Ralph– Ralph2010-11-30 12:03:18 +00:00Commented Nov 30, 2010 at 12:03
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7 Answers
You have ArrayList all wrong,
- You can't have an integer array and assign a string value.
- You cannot do a
add()method in an array
Rather do this:
List<String> alist = new ArrayList<String>();
alist.add("apple");
alist.add("banana");
alist.add("orange");
String value = alist.get(1); //returns the 2nd item from list, in this case "banana"
Indexing is counted from 0 to N-1 where N is size() of list.
Comments
Using an Array:
String[] fruits = new String[3]; // make a 3 element array
fruits[0]="apple";
fruits[1]="banana";
fruits[2]="orange";
System.out.println(fruits[1]); // output the second element
Using a List
ArrayList<String> fruits = new ArrayList<String>();
fruits.add("apple");
fruits.add("banana");
fruits.add("orange");
System.out.println(fruits.get(1));
Comments
Exactly as arrays in all C-like languages. The indexes start from 0. So, apple is 0, banana is 1, orange is 2 etc.
Comments
In order to store Strings in an dynamic array (add-method) you can't define it as an array of integers ( int[3] ). You should declare it like this:
ArrayList<String> alist = new ArrayList<String>();
alist.add("apple");
alist.add("banana");
alist.add("orange");
System.out.println( alist.get(1) );
Comments
The big difference between primitive arrays & object-based collections (e.g., ArrayList) is that the latter can grow (or shrink) dynamically. Primitive arrays are fixed in size: Once you create them, their size doesn't change (though the contents can).
Comments
Here is how I would write it.
String[] fruit = "apple banana orange".split(" ");
System.out.println(fruit[1]);
1 Comment
Mot
You are not serious, are you? Why not write your first line as
String[] fruit = "applesbananasorange".replace('s', ' ').split(" ");? The CPU should be used, if there is already one.