django rest framework: Get url path variable in a view

Question

I have to pass the product_id (which is a string) into a view. There I have to do some DB operations based on the product id. How can I get that product id in that view? Actually what should be the parameter in the class ProductDetailConfiguration view? Now I am passing viewsets.ModelViewSet. Actually, this API call is not completely related to any model.

# urls.py

  url(r'^product-configuration/(?P<product_id>[\w-]+)/$', views.ProductDetailConfiguration, name='product-configuration'),

# views.py

class ProductDetailConfiguration(viewsets.ModelViewSet):

    queryset = Product.objects.all()

    def get_queryset(self, **kwargs):
      
        queryset = Product.objects.all()
        product_id = self.request.get('product_id', None)
        #filter query set based on the product_id
        return queryset

    serializer_class = ProductConfigurationSerializer

Community · Accepted Answer · 2020-06-20 09:12:55Z

25

The URL parameters are available in self.kwargs.
From the documentation:

Filtering against the URL

Another style of filtering might involve restricting the queryset based on some part of the URL.

For example if your URL config contained an entry like this:
url('^purchases/(?P<username>.+)/$', PurchaseList.as_view()),
You could then write a view that returned a purchase queryset filtered by the username portion of the URL:
class PurchaseList(generics.ListAPIView):
   serializer_class = PurchaseSerializer

   def get_queryset(self):
       """
       This view should return a list of all the purchases for
       the user as determined by the username portion of the URL.
       """
       username = self.kwargs['username']
       return Purchase.objects.filter(purchaser__username=username)

edited Jun 20, 2020 at 9:12

CommunityBot

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answered Aug 15, 2018 at 13:55

OrangeDog

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1 Comment

Akhil S Over a year ago

self.kwargs['param'] -> this is the right answer

Community · Accepted Answer · 2017-05-23 12:25:40Z

2

You have to use lookup_field in your views to get product_id and the view should not belongs to any model. Here I already answer a question like yours using django rest framework to return info by name

Hope this will help to solve your problem.

edited May 23, 2017 at 12:25

CommunityBot

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answered Apr 19, 2017 at 7:33

mohammadjh

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2 Comments

Arun SS Over a year ago

I have implemented like you suggested in that question. When I print the queryset in view it shows the result. ProductConfigurationCustomSerializer(queryset). Then what should be the model in serializer. When I commented the model references it throws error.

mohammadjh Over a year ago

Actually, what do you want to do? In your question, you just asked for getting product_id in views.

Phuong Vu · Accepted Answer · 2017-04-19 07:19:22Z

0

This is my approach:

Update URL:

url(r'^product-configuration$', views.ProductDetailConfiguration, name='product-configuration'),

In view.py:

class ProductDetailConfiguration(viewsets.ModelViewSet):
    lookup_field = 'product_id'
    serializer_class = ProductConfigurationSerializer

    def retrieve(request, product_id=None, *args, **kwargs):
        queryset = self.get_queryset()
        # Filter with produc_id
        # print(product_id)
        # Return Response

answered Apr 19, 2017 at 7:19

Phuong Vu

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Comments

Ajay Aneja · Accepted Answer · 2017-04-19 07:31:47Z

-1

You can get the data from the request url by :- data_dict = self.request.data This will return a dictionary of all the parameters of the request url. You can use the parameter name as the key

answered Apr 19, 2017 at 7:31

Ajay Aneja

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1 Comment

OrangeDog Over a year ago

URL parameters are not in there.

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