Call to a member function links() on array in Laravel error

Question

I was working with Laravel and I am trying to paginate my table of books. I got this error "Call to a member function links() on array in Laravel". It may be as the duplicate's error, but I still can't figure out how to solve my thing.

BookController fiddle:

public function index()
{
    $books = Book::simplePaginate(3)->all();
    $authors = Author::all();
    $genres = Genre::all();
    return view('books.all')->withBooks($books)->withAuthors($authors)->withGenres($genres);
}

books/all.blade.php fiddle

<table class="table table-hover">
  <tr class="info">
  <td>#</td>
  <td>Name</td>
  <td>Author</td>
  <td><center>Visit</center></td>
  </tr>
  @foreach($books as $book)
  <tr>
    <td width="50px"><img width="50px" height="75px" src="{{ asset('images/' . $book->image) }}"></td>
    <td width="50px">{{ $book->name }}</td>
    <td width="50px">{{ $book->author->name }}</td>
    <td width="50px"><center><a href="{{ url('books', $book->id) }}"><button class="btn btn-success">Visit</button></a></td>
 </tr>
@endforeach
</table> 
{{ $books->links() }}

Possible duplicate of Laravel Call to a member function toArray() on array Error — Marcin Orlowski
– Marcin Orlowski, Commented Apr 28, 2017 at 12:38
Try this $books=DB::table('books')->paginate(3); instead of $books = Book::simplePaginate(3)->all(); — Nil
– Nil, Commented Apr 28, 2017 at 12:42

Irfan · Accepted Answer · 2017-04-28 13:29:39Z

2

Just remove the ->all() method from the $books variable.

$books = Book::paginate(10);

paginate() function considers taking all content from the table, which is taken here by Book model

answered Apr 28, 2017 at 13:29

Irfan

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