Standard way to encode an URL given a base URL and a Map<String,String> with parameters

Question

we're looking for a standard way to encode a URL given a predefined base URL and a Map of parameters and values. Ideally the method is declarated as something like

String constructURL( String baseURL, Map<String,String> parameters)

would work like the following snippet

Map<String, String> params = new HashMap<String,String>();
params.put("p1", "v1");
params.put("p2", "v2");
String url = constructURL( "page.html", params);

and url would have the following value

"page.html?p1=v1&p2=v2"

Btw, we're using Apache Click with Tomcat.

madhurtanwani · Accepted Answer · 2010-12-13 12:38:57Z

2

The JDK's URLEncoder should work for your use case. Like this :

String constructURL(String base, Map<String, String> params) {
  StringBuilder url = new StringBuilder(base);
  if(params != null && params.size() > 0) {
  url.append("?");
  for(Map.Entry<String, String> entry : params.entrySet()) {
      url.append(entry.getKey());
      url.append("=");
      url.append(URLEncoder.encode(entry.getValue()));
      url.append("&");   //not for the last one (but should be OK)
    }
  }

return url.toString();
}

answered Dec 13, 2010 at 12:38

madhurtanwani

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1 Comment

mvaz Over a year ago

Thanks for the code, but building my own function is exactly what I was trying to avoid.

Valentin Rocher · Accepted Answer · 2010-12-13 12:30:29Z

1

You can use URLCodec from Commons Codec to create the url-encoded version of your parameters, and then loop on the parameters to create the query. Have a look at the source of URLEncodedUtils class in Apache HttpClient to see an example of what I explain.

answered Dec 13, 2010 at 12:30

Valentin Rocher

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