echo specific part of array in php

Question

I'm still learning php arrays and I'm trying to echo a

array(8) { [0]=> string(9) "site_name" [1]=> string(3) "url" [2]=> string(5) "title" [3]=> string(11) "description" [4]=> string(4) "type" [5]=> string(5) "image" [6]=> string(11) "image:width" [7]=> string(12) "image:height" } NULL site_name => Playbuzzurl => http://www.playbuzz.com/jordonr10/what-modern-societal-archetype-fits-your-personalitytitle => What Modern Societal Archetype Fits Your Personality?description => It's 2017, so it's about time we update the books!type => articleimage => http://cdn.playbuzz.com/cdn/aef166e1-1574-4d57-9823-3f38f30bcfc4/810f1d3e-0a97-4797-8235-b4c988562a1c.jpgimage:width => 1600image:height => 842

array(8) { [0]=> string(9) "site_name" [1]=> string(3) "url" [2]=> string(5) "title" [3]=> string(11) "description" [4]=> string(4) "type" [5]=> string(5) "image" [6]=> string(11) "image:width" [7]=> string(12) "image:height" } NULL site_name => Playbuzzurl => http://www.playbuzz.com/jordonr10/what-modern-societal-archetype-fits-your-personalitytitle => What Modern Societal Archetype Fits Your Personality?description => It's 2017, so it's about time we update the books!type => articleimage => http://cdn.playbuzz.com/cdn/aef166e1-1574-4d57-9823-3f38f30bcfc4/810f1d3e-0a97-4797-8235-b4c988562a1c.jpgimage:width => 1600image:height => 842

I'm trying to echo just the value for description which is It's 2017, so it's about time we update the books!

I've tried several different things, but nothing works. Any help is greatly appreciated.

echo $array[0]['description'];      // returns nothing
var_dump($key);                     // returns string(12) "image:height"

Current Code

<?php
require_once('OpenGraph.php');

$graph = OpenGraph::fetch('http://www.playbuzz.com/jordonr10/what-modern-societal-archetype-fits-your-personality');
var_dump($graph->keys());
var_dump($graph->schema);

foreach ($graph as $key => $value) {
    echo "$key => $value<br><hr>";
}
echo "Value Below<hr>";
echo $array['description'];

?>

the value of the description is outside of your array. You need to put it in an array first before you are able to get it. — Long Kim
– Long Kim, Commented Jun 7, 2017 at 5:16

B. Desai · Accepted Answer · 2017-06-07 05:37:33Z

1

From your code its seems that you can directly get value of description from $graph if key is already there. Also you are trying to diplay $array['description']; here I can see $array is define any where

try to

 echo $graph['description']; // if $graph is array

OR

echo $graph->description; // If its an object

answered Jun 7, 2017 at 5:37

B. Desai

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2 Comments

Mr. B Over a year ago

It is an Object. That explains why everything I was trying was failing. How do you tell the difference between object and array in the above? Thanks again!

B. Desai Over a year ago

Use var_dump($graph); The result will show you whether it is object or an array

justyand · Accepted Answer · 2017-06-07 05:17:58Z

0

Just call

echo $array[3];

Or use associative arrays which can be called

echo $array['description'];

http://php.net/manual/en/language.types.array.php

answered Jun 7, 2017 at 5:17

justyand

316 bronze badges

4 Comments

Mr. B Over a year ago

Hey justyand, Thanks for offering assistance. I did try both of those too, but neither work. Any other ideas?

justyand Over a year ago

No problem. First place your code. Then we can talk about malfunctioning. Basicaly first define an array, then call echo

mickmackusa Over a year ago

@Mr.B your question doesn't make sense, read first comment under your question.

justyand Over a year ago

So from code it's obvious that $array is not defined You have to use $graph

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