Slicing a 2D numpy array into a 1D array

Question

I have a 2D numpy array, FilteredOutput, that has 2 columns and 10001 rows, though the number of rows is a variable.

I am trying to take the 2nd column of FilteredOutput and use it to populate a new 1D numpy array called timeSeriesArray using some code I found):

timeSeriesArray = np.array(FilteredOutput[:,0])

But I am getting the following error message:

TypeError: list indices must be integers, not tuple

Why?

If you want the second column, you should probably use [:,1]. — mtrw
– mtrw, Commented Dec 31, 2010 at 8:46

Michael B. Currie · Accepted Answer · 2015-08-19 20:31:04Z

1

This is solved now. The problem was that I had not explicitly declared FilteredOutput to be a numpy array inside the function. I thought it had been declared as a numpy array outside the function, but the problem was solved when I added

FilteredOutput = np.array(FilteredOutput)

before

timeSeriesArray = np.array(FilteredOutput[:,0])

note: numpy is imported as np

edited Aug 19, 2015 at 20:31

Michael B. Currie

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answered Dec 31, 2010 at 8:42

MedicalMath

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