filter array object using multiple value from array using javascript or jquery

Question

the row users array looks like.

var users = [{name: 'John',address: 'USA',year:2010 },{name: 'John',address: 'USA',year:2011 },{name: 'John',address: 'USA',year:2012 },{name: 'John',address: 'USA',year:2013 },{name: 'John',address: 'USA',year:2014}];

the filter array is,

var filter_year = ['2010','2011','2012'];

how i can get the result array of filtered using years in filter_year, i need to get result array like.

var users = [{name: 'John',address: 'USA',year:2010 },{name: 'John',address: 'USA',year:2011 },{name: 'John',address: 'USA',year:2012 }];

You'll have to iterate the json and push only those json objects whose year exist in filter_year — Parag Jadhav
– Parag Jadhav, Commented Sep 7, 2017 at 4:30

prasanth · Accepted Answer · 2017-09-07 04:39:35Z

1

You can use below code to get all users for given years.

var filter_year = ['2010','2011','2012'],
    users = [{name: 'John',address: 'USA',year:2010 },{name: 'John',address: 'USA',year:2011 },{name: 'John',address: 'USA',year:2012 },{name: 'John',address: 'USA',year:2013 },{name: 'John',address: 'USA',year:2014}],
    filteredUsers = []
    allYears = filter_year.join("|");
    
    for(var user in users) { 
    	if(allYears.indexOf(users[user].year) !== -1) {
      		filteredUsers.push(users[user]);
       }
    }
    
    console.log(filteredUsers);

edited Sep 7, 2017 at 4:39

prasanth

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answered Sep 7, 2017 at 4:38

Ankit Shah

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Comments

adeneo · Accepted Answer · 2017-09-07 04:32:01Z

0

Just filter one array based on inclusion in the other array

var users = [{name: 'John',address: 'USA',year:2010 },{name: 'John',address: 'USA',year:2011 },{name: 'John',address: 'USA',year:2012 },{name: 'John',address: 'USA',year:2013 },{name: 'John',address: 'USA',year:2014}];

var filter_year = ['2010','2011','2012'];

var result = users.filter( item => filter_year.includes(item.year+""));

console.log(result)

Note that the years are integers in one array, and strings in the other

answered Sep 7, 2017 at 4:32

adeneo

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2 Comments

Nisarg Shah Over a year ago

Why did you use item.year + "" instead of item.year.toString()? Does it have any performance benefits?

adeneo Over a year ago

@NisargShah - Don't know, but it probably doesn't matter performance-wise, they both do the same thing, coerce to a string

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