Aws Lambda: How to get query params from Api Gateway in lambda function implemented in Java

Question

Aws Lambda - How to get query params from Api Gateway in lambda function implemented in Java.

I have following code snippet :

package com.amazonaws.lambda.demo;

import com.amazonaws.services.lambda.runtime.Context;
import com.amazonaws.services.lambda.runtime.RequestHandler;

public class LambdaFunctionHandler implements RequestHandler<String, String> {

    @Override
    public String handleRequest(String input, Context context) {
        context.getLogger().log("Input: " + input);

        // TODO: implement your handler
        return "Hello from " + input;
    }
}

How can i access query params if any in above handleRequest function.

Alex Savitsky · Accepted Answer · 2020-01-15 21:34:06Z

7

in pom.xml make sure "2.2.5" or newer version is specified here

<dependency>
  <groupId>com.amazonaws</groupId>
  <artifactId>aws-lambda-java-events</artifactId>
  <version>2.2.5</version>
</dependency>

Your java lambda class:

import com.amazonaws.services.lambda.runtime.events.APIGatewayProxyRequestEvent;
import com.amazonaws.services.lambda.runtime.events.APIGatewayProxyResponseEvent;

public class LambdaFunctionHandler
    implements RequestHandler<APIGatewayProxyRequestEvent, APIGatewayProxyResponseEvent> {
    @Override
    public APIGatewayProxyResponseEvent handleRequest(APIGatewayProxyRequestEvent input,
            Context context) {
        Map<String, String> inputParams = input.getPathParameters();

        APIGatewayProxyResponseEvent responseEvent = new APIGatewayProxyResponseEvent();
        responseEvent.setBody("body text");
        responseEvent.setStatusCode(200);
        return responseEvent;
    }
}

edited Jan 15, 2020 at 21:34

Alex Savitsky

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answered Jan 15, 2020 at 21:05

tgk23

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2 Comments

Sunny Over a year ago

This did not work for me. Do I need to configure something else also?

G M Over a year ago

AWS should use your answer for the official documentation; this is the most-complete 'template' that I've found for Lambdas for Java. It's minimal and gives you all of the types you need to process HTTP requests. Would upvote more than once if I could!

j3App · Accepted Answer · 2021-06-10 09:13:58Z

Based on tgk23's answer above, I believe you are looking for the query parameters, not the path parameters:

public class LambdaFunctionHandler
        implements RequestHandler<APIGatewayProxyRequestEvent, APIGatewayProxyResponseEvent> {
    @Override
    public APIGatewayProxyResponseEvent handleRequest(APIGatewayProxyRequestEvent input, Context context) {
        Map<String, String> inputParams = input.getQueryStringParameters();
        for (Map.Entry<String, String> entry : inputParams.entrySet()) {
            LOGGER.info("param: " + entry.getKey() + "=" + entry.getValue());
        }

        APIGatewayProxyResponseEvent responseEvent = new APIGatewayProxyResponseEvent();
        responseEvent.setBody("body text");
        responseEvent.setStatusCode(200);
        return responseEvent;
    }
}

Vijayanath Viswanathan · Accepted Answer · 2017-09-26 16:55:36Z

0

You can try mapping everything you want in integration request body mapping template of API Gateway. Once you construct body mapping template then in the context of lambda you will get the excat json you have constructed.

Please find below link, which I have given a solution for similar kind of question,

https://stackoverflow.com/a/46407780/7666972

answered Sep 26, 2017 at 16:55

Vijayanath Viswanathan

8,6713 gold badges31 silver badges50 bronze badges

1 Comment

Mohit Gupta Over a year ago

Thanks Vijayanath , i will try this and come back.

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