syntax error near unexpected token error in shell script

Question

i have the following shell script-

#!/bin/bash
echo "enter the full path of script";
read path;
while true
    ps aux | grep -v grep | grep -q $path || ( nohup php -f $path & )
done

I am executing in following way -

bash test.sh
enter the full path of script
php_test.php
test.sh: line 7: syntax error near unexpected token `done'
test.sh: line 7: `done'

there is a php_test.php in the same directory as the present one. PLease help. Thanks in advance.

Also escape $path with double quotes to prevent spaces in the variable to have bash consider it as two arguments after expansion. — Benoit
– Benoit, Commented Jan 10, 2011 at 9:17

Ignacio Vazquez-Abrams · Accepted Answer · 2011-01-10 09:15:12Z

4

From help while:

while: while COMMANDS; do COMMANDS; done

You're missing the do.

while true
do
 ...
done

answered Jan 10, 2011 at 9:15

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