How do I assign an argument to a string array?

Question

int main(int argc, char **argv) {
  char username[256];
  username = ?;
}

thanks~

What if I pass 257 characters?

SLaks
– SLaks

2011-01-11 04:03:01 +00:00
Commented Jan 11, 2011 at 4:03 — SLaks
– SLaks, Commented Jan 11, 2011 at 4:03

zwol · Accepted Answer · 2011-01-11 04:09:21Z

7

You probably want to make username be a pointer, then you can just assign it:

int
main(int argc, const char *const *argv)
{
    const char *username;
    if (argc >= 2)
        username = argv[1];
    else
    {
        fprintf(stderr, "usage: %s username ...\n", argv[0]);
        return 2;
    }
    /* ... */
}

But if you really want to copy the contents of the array, you are looking for strncpy.

answered Jan 11, 2011 at 4:09

zwol

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Raph Levien · Accepted Answer · 2011-01-11 04:08:36Z

2

If you want to copy another string (like argv[1]), then you probably want to use strncpy ( http://strncpy.org/ ). If you want to input it from stdin, then http://en.wikipedia.org/wiki/Fgets is probably a better bet.

answered Jan 11, 2011 at 4:08

Raph Levien

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