How to sort a string according to integers in JavaScript?

Question

//This is a function to sort a string according to integers

function order(words) {
    var str = words.split(' ');
    var newArr = [];
    console.log(str);
    console.log('----');
    for (var i = 0; i < str.length; i++) {
        var sorted = str[i].split('').sort();
        newArr.push(sorted);
    }
    console.log(newArr);
    var newar = [];
    for (var j = 0; j < newArr.length; j++) {
        newar += newArr[j].join('') + ' ';
    }
    console.log(newar.trim().split(' ').sort().join(' '));
}
order("is2 Thi1s T4est 3a");

//Result should be: Thi1s is2 3a T4est

What if a word contains more than one number or no numbers at all? — Aluan Haddad
– Aluan Haddad, Commented Oct 30, 2017 at 16:03

Nina Scholz · Accepted Answer · 2017-10-30 16:07:54Z

6

Assuming, only one number is in a splitted string, then you could match a number and take it for sorting.

function order(string) {
    function getNumber(s) { return +s.match(/\d+/)[0] || 0; }

    return string
        .split(' ')
        .sort(function (a, b) { return getNumber(a) - getNumber(b); })
        .join(' ');
}

console.log(order("is2 Thi1s T4est 3a"));

edited Oct 30, 2017 at 16:07

answered Oct 30, 2017 at 16:05

Nina Scholz

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Comments

yuantonito · Accepted Answer · 2017-10-30 16:14:34Z

2

In one line:

function order(words) {
    return words
        .split(' ')
        .sort((a, b) => a.match(/\d+/) - b.match(/\d+/))
        .join(' ');
}

edited Oct 30, 2017 at 16:14

answered Oct 30, 2017 at 16:06

yuantonito

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1 Comment

GGO Over a year ago

This regex, will only match number from 0 to 9. Add \d+ regex to get all decimal value from 0 to 99999999...

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