JavaScript: sorting string according to numbers it contains

Question

I am trying to sort a string which contains a single number from 1-9. For e.g. string is "Ho2w are1 y3ou" then resulting string should be "are1 Ho2w y3ou". For that, I have used for...of loop to iterate over a string and used split to convert it into an array of string and then used sort method but I am not getting an output. Can anyone suggest what's wrong in my program?

code ::

function order(words){
let result = "";
for (let value of words) {
  result += value;
}

let splited = result.split(" ");
  if(words === ""){
    return "";
  }
  return splited.sort((a,b) => a - b);

}

order("Ho2w are1 y3ou");

result is not defined anywhere?

Mark
– Mark

2018-10-20 19:19:01 +00:00
Commented Oct 20, 2018 at 19:19 — Mark
– Mark, Commented Oct 20, 2018 at 19:19
Defined it in program

Riya
– Riya

2018-10-20 19:21:32 +00:00
Commented Oct 20, 2018 at 19:21 — Riya
– Riya, Commented Oct 20, 2018 at 19:21

Mark · Accepted Answer · 2018-10-20 19:25:14Z

3

You need to somehow find the number in the word that you want to use to sort. One way to do this is with String.match() and a regular expression:

let str =  "Ho2w are1 y3ou"

let sorted = 
str.split(' ')
.sort((a,b) => a.match(/\d+/)[0] -  b.match(/\d+/)[0]) // sort based on first number found
.join(' ')

console.log(sorted)

edited Oct 20, 2018 at 19:25

answered Oct 20, 2018 at 19:23

Mark

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7 Comments

Riya Over a year ago

Then no need to use for...of loop ?

Mark Over a year ago

No need for the for loop. split() makes and array. sort() sorts it, and join() puts it back together as a string.

Ele Over a year ago

Why match? the replace function is a better suit for this question.

Mark Over a year ago

@Ele, match was the first things that came to mind. Why is replace better?

Riya Over a year ago

Thanks @MarkMeyer for your answer.

|

Ele · Accepted Answer · 2018-10-20 19:32:28Z

0

You can use the regexp /\s+/ for splitting the array, that way you can match the tab too. And the regexp [^\d+]/g to remove those chars which are not a number and make the comparison with numbers only.

let str = "Ho2w are1 y3ou"

let sorted = str.split(/\s+/)
  .sort((a, b) => a.replace(/[^\d+]/g, '') - b.replace(/[^\d+]/g, '')).join(' ');

console.log(sorted);

answered Oct 20, 2018 at 19:32

Ele

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Comments

slider · Accepted Answer · 2018-10-20 19:57:12Z

0

You can also extract characters using filter and isNaN and then use parseInt to get their integer value to use for your sorting function.

const str = "are1 Ho2w y3ou";

const ordered = str.split(" ").sort((a, b) => {
  let numA = parseInt([...a].filter(c => !isNaN(c)).join(''));
      numB = parseInt([...b].filter(c => !isNaN(c)).join(''));
  return numA - numB;
}).join(' ');

console.log(ordered);

edited Oct 20, 2018 at 19:57

answered Oct 20, 2018 at 19:32

slider

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